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IS method of mix design steps

Short answer

Determine target mean strength (f_ck + 1.65s). Select w/c ratio from strength vs w/c relationship and durability limits. Find water content from table for max aggregate size and slump, adjust. Calculate cement content. Determine volume of coarse aggregate per unit total aggregate from zone and w/c. Compute aggregate masses using absolute volume method.

Describe the stepwise process of concrete mix design by the IS method (conceptual steps; show sample table and graph wherever possible).

The IS method (IS 10262:2009, revised in 2019) designs a mix for a required grade from the target strength, w/c ratio, water content and aggregate proportions by absolute volume, and is used with IS 456.

Steps

  1. Design data: grade, maximum aggregate size, workability, exposure, cement type, specific gravities, absorption.
  2. Target mean strength: fck′=fck+1.65sf'_{ck} = f_{ck} + 1.65 s (s from Table 1 of IS 10262: M20 4.0, M25 4.0, M30 5.0, M35 5.0 N/mm2^2; add 1 N/mm2^2 if site control is only fair). The 2019 revision also requires fck′≥fck+Xf'_{ck} \geq f_{ck} + X (X = 5.0, 5.5, 6.5 for M10-15, M20-25, M30 and above); take the higher value.
  3. w/c ratio from the strength vs w/c relationship for the materials (in the 2019 revision, the curves of Fig 1 for 33/43/53 grade cement) for the target strength; check against the IS 456 Table 5 limits for the exposure; adopt the lower.
  4. Water content from Table 2 (186 kg/m3^3 for 20 mm angular aggregate at 50 mm slump); add 3% for every 25 mm of extra slump; reduce when a superplasticiser is used (by 20% or more).
  5. Cement content = water / (w/c); check the minimum from IS 456 Table 5 and the maximum of 450 kg/m3^3.
  6. Volume of coarse aggregate per unit volume of total aggregate from Table 3 (maximum size and zone of fine aggregate, for w/c 0.5); adjust by ±\pm 0.01 for each ∓\mp 0.05 change in w/c.
  7. Mix calculations per m3^3 using absolute volumes:
Vagg=1−[Cρc1000+W1000+admixρa1000+air]V_{agg} = 1 - \left[\frac{C}{\rho_c 1000} + \frac{W}{1000} + \frac{\text{admix}}{\rho_a 1000} + \text{air}\right]

Mass of CA = Vagg×VCA×SGCA×1000V_{agg} \times V_{CA} \times SG_{CA} \times 1000; FA = Vagg(1−VCA)×SGFA×1000V_{agg} (1 - V_{CA}) \times SG_{FA} \times 1000 (entrapped air taken as 2% for 20 mm). 8. Trial mixes: three trials with the w/c varied; check the strength and slump; select the best. 9. Apply moisture and absorption corrections.

Sample table (SG of CA 2.74, FA 2.65)

ItemValue
Grade / targetM30 / 38.25
w/c0.43
Water, cement186, 433 kg
VCAV_{CA}0.634
FA, CA637, 1141 kg

Graph

 f_target (MPa)
  50|\
  40| `.\
  38|---`-`.   <- read w/c = 0.43
  30|       `-.
    +-----------> w/c
     0.35  0.5

✓ Answer checked by Claude Opus 5.5 (high effort)

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