- 2074 Chaitra · 2+2+3+3 marks
RC impedance properties; Foster I and Cauer I
Short answer
RC impedance has simple poles and zeros on the negative real axis, alternating, with lowest a pole and highest a zero; Z(0)>Z(∞). Valid: (s+3)(s+7)/((s+1)(s+5)). Foster I: series 1Ω, parallel 3Ω||1/3F, 0.2Ω||1F. Cauer I: series 1Ω, shunt 0.25F, series 2Ω, shunt 0.333F, series 1.2Ω.
What are the properties of RC impedance function? Which of the following is valid RC impedance function? State with reason. Pick a valid RC impedance function and realize it using foster I and cauer I method. z(s) = 3(s²+2)/(s²+1); z(s) = (s+1)(s+5)/((s+3)(s+7)); z(s) = (s+3)(s+7)/((s+1)(s+5)); z(s) = (s+1)(s+3)/((s+4)(s+5))
Properties of RC impedance function
An RC driving-point impedance has these properties:
- All poles and zeros are simple and lie on the negative real axis of the -plane (including the origin).
- Poles and zeros alternate along the negative real axis.
- The critical frequency nearest the origin (lowest) is a pole; it may be at .
- The critical frequency farthest from the origin is a zero; it may be at .
- , and is a constant (no pole at infinity).
- Residues of at its poles are real and positive; on the real axis .
- The same form describes an RL admittance .
Testing the functions
| Function | Critical frequencies | Result |
|---|---|---|
| poles at , zeros at | On the axis, not the negative real axis → invalid | |
| z 1, p 3, z 5, p 7 | Lowest is a zero; → invalid | |
| p 1, z 3, p 5, z 7 | Lowest a pole, highest a zero, alternate; → valid | |
| z 1, z 3, p 4, p 5 | Not alternating, lowest is a zero → invalid |
Realize .
Foster-I realization
Expand in partial fractions; every residue must be positive:
| Term | Rule | Element value |
|---|---|---|
| (series) | 1 Ω | |
| (pole at ) | , | = 3 Ω, = 1/3 F (≈ 0.3333 F) |
| (pole at ) | , | = 1/5 Ω (≈ 0.2 Ω), = 1 F |
o--[R1]--[R2||C2]--[R3||C3]--o
Cauer-I realization
Divide with descending powers (continued fraction about ). For an RC impedance the quotients alternate between a constant (series ) and (shunt ):
- → remove , giving series = 1 Ω; remainder .
- → remove , giving shunt = 1/4 F (≈ 0.25 F); remainder .
- → remove , giving series = 2 Ω; remainder .
- → remove , giving shunt = 1/3 F (≈ 0.3333 F); remainder .
- → remove , giving series = 6/5 Ω (≈ 1.2 Ω); remainder .
| Element | Position | Value |
|---|---|---|
| series | 1 Ω | |
| shunt | 1/4 F (≈ 0.25 F) | |
| series | 2 Ω | |
| shunt | 1/3 F (≈ 0.3333 F) | |
| series | 6/5 Ω (≈ 1.2 Ω) |
o--[R1]----+---[R3]----+---[R5]-+
| | |
[C2] [C4] |
| | |
o----------+-----------+--------+
✓ Answer checked by Claude Sonnet 5.5
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