Skip to main content

RC impedance properties; Foster I and Cauer I

Short answer

RC impedance has simple poles and zeros on the negative real axis, alternating, with lowest a pole and highest a zero; Z(0)>Z(∞). Valid: (s+3)(s+7)/((s+1)(s+5)). Foster I: series 1Ω, parallel 3Ω||1/3F, 0.2Ω||1F. Cauer I: series 1Ω, shunt 0.25F, series 2Ω, shunt 0.333F, series 1.2Ω.

What are the properties of RC impedance function? Which of the following is valid RC impedance function? State with reason. Pick a valid RC impedance function and realize it using foster I and cauer I method. z(s) = 3(s²+2)/(s²+1); z(s) = (s+1)(s+5)/((s+3)(s+7)); z(s) = (s+3)(s+7)/((s+1)(s+5)); z(s) = (s+1)(s+3)/((s+4)(s+5))

Properties of RC impedance function

An RC driving-point impedance ZRC(s)Z_{RC}(s) has these properties:

  1. All poles and zeros are simple and lie on the negative real axis of the ss-plane (including the origin).
  2. Poles and zeros alternate along the negative real axis.
  3. The critical frequency nearest the origin (lowest) is a pole; it may be at s=0s=0.
  4. The critical frequency farthest from the origin is a zero; it may be at s=∞s=\infty.
  5. ZRC(0)>ZRC(∞)Z_{RC}(0) > Z_{RC}(\infty), and ZRC(∞)≥0Z_{RC}(\infty)\ge 0 is a constant (no pole at infinity).
  6. Residues of ZRC(s)Z_{RC}(s) at its poles are real and positive; on the real axis dZ(σ)/dσ<0dZ(\sigma)/d\sigma<0.
  7. The same form describes an RL admittance YRL(s)Y_{RL}(s).

Testing the functions

FunctionCritical frequenciesResult
3(s2+2)s2+1\dfrac{3(s^2+2)}{s^2+1}poles at s=±j1s=\pm j1, zeros at ±j1.414\pm j1.414On the jωj\omega axis, not the negative real axis → invalid
(s+1)(s+5)(s+3)(s+7)\dfrac{(s+1)(s+5)}{(s+3)(s+7)}z 1, p 3, z 5, p 7Lowest is a zero; Z(0)=0.238<Z(∞)=1Z(0)=0.238 < Z(\infty)=1 → invalid
(s+3)(s+7)(s+1)(s+5)\dfrac{(s+3)(s+7)}{(s+1)(s+5)}p 1, z 3, p 5, z 7Lowest a pole, highest a zero, alternate; Z(0)=4.2>Z(∞)=1Z(0)=4.2 > Z(\infty)=1 → valid
(s+1)(s+3)(s+4)(s+5)\dfrac{(s+1)(s+3)}{(s+4)(s+5)}z 1, z 3, p 4, p 5Not alternating, lowest is a zero → invalid

Realize Z(s)=(s+3)(s+7)(s+1)(s+5)=s2+10s+21s2+6s+5Z(s) = \dfrac{(s+3)(s+7)}{(s+1)(s+5)} = \dfrac{s^2+10s+21}{s^2+6s+5}.

Foster-I realization

Expand Z(s)Z(s) in partial fractions; every residue must be positive:

k∞=Z(∞)=1k2=[(s+1)Z(s)]s=−1=3k3=[(s+5)Z(s)]s=−5=1\begin{aligned} k_\infty &= Z(\infty) = 1 \\ k_{2} &= [(s+1)Z(s)]_{s=-1} = 3 \\ k_{3} &= [(s+5)Z(s)]_{s=-5} = 1 \end{aligned} Z(s)=1+3s+1+1s+5Z(s) = 1 + \frac{3}{s + 1} + \frac{1}{s + 5}
TermRuleElement value
R1R_1 (series)k∞k_\infty1 Ω
R2∥C2R_2 \parallel C_2 (pole at −1-1)C=1/kC=1/k, R=k/σR=k/\sigmaR2R_2 = 3 Ω, C2C_2 = 1/3 F (≈ 0.3333 F)
R3∥C3R_3 \parallel C_3 (pole at −5-5)C=1/kC=1/k, R=k/σR=k/\sigmaR3R_3 = 1/5 Ω (≈ 0.2 Ω), C3C_3 = 1 F
o--[R1]--[R2||C2]--[R3||C3]--o

Cauer-I realization

Divide with descending powers (continued fraction about s=∞s=\infty). For an RC impedance the quotients alternate between a constant (series RR) and ksks (shunt CC):

  1. Z1(s)=s2+10s+21s2+6s+5Z_1(s) = \frac{s^{2} + 10 s + 21}{s^{2} + 6 s + 5} → remove 11, giving series R1R_1 = 1 Ω; remainder 4(s+4)(s+1)(s+5)\frac{4 \left(s + 4\right)}{\left(s + 1\right) \left(s + 5\right)}.
  2. Y2(s)=s2+6s+54s+16Y_2(s) = \frac{s^{2} + 6 s + 5}{4 s + 16} → remove s4\frac{s}{4}, giving shunt C2C_2 = 1/4 F (≈ 0.25 F); remainder 2s+54(s+4)\frac{2 s + 5}{4 \left(s + 4\right)}.
  3. Z3(s)=4s+162s+5Z_3(s) = \frac{4 s + 16}{2 s + 5} → remove 22, giving series R3R_3 = 2 Ω; remainder 62s+5\frac{6}{2 s + 5}.
  4. Y4(s)=2s+56Y_4(s) = \frac{2 s + 5}{6} → remove s3\frac{s}{3}, giving shunt C4C_4 = 1/3 F (≈ 0.3333 F); remainder 56\frac{5}{6}.
  5. Z5(s)=65Z_5(s) = \frac{6}{5} → remove 65\frac{6}{5}, giving series R5R_5 = 6/5 Ω (≈ 1.2 Ω); remainder 00.
ElementPositionValue
R1R_1series1 Ω
C2C_2shunt1/4 F (≈ 0.25 F)
R3R_3series2 Ω
C4C_4shunt1/3 F (≈ 0.3333 F)
R5R_5series6/5 Ω (≈ 1.2 Ω)
o--[R1]----+---[R3]----+---[R5]-+
           |           |        |
         [C2]        [C4]       |
           |           |        |
o----------+-----------+--------+

✓ Answer checked by Claude Sonnet 5.5

All Filter Design chapter 4 questions →