- 2082 Bhadra · 4 marks
Terzaghi's bearing capacity theory
Short answer
Terzaghi's theory gives ultimate bearing capacity for a shallow strip footing with a rough base, considering equilibrium of a failure wedge. Assumptions: strip footing (plane strain), Df ≤ B, rough base, homogeneous isotropic soil obeying Mohr-Coulomb, shear strength above base ignored (replaced by surcharge q = γ Df), general shear failure, vertical central load. The equation is qu = cNc + γ Df Nq + 0.5 γ B Nγ. For local shear, c and tanφ are reduced to two-thirds.
Discuss Terzaghi's bearing capacity theory. Also state the assumptions.
Terzaghi's theory (1943) gives the ultimate bearing capacity of a shallow footing by considering the equilibrium of a failure wedge. It is the most widely used classical theory and extends Prandtl's and Reissner's work by including soil weight and a rough base.
Assumptions
- The footing is a long strip (plane strain), and (shallow foundation).
- The base is rough, so the soil wedge directly below it stays elastic and moves down with the footing.
- The soil is homogeneous and isotropic, and obeys Mohr–Coulomb's law .
- The shear strength of the soil above the base level is ignored. It is replaced by a uniform surcharge .
- Failure occurs in general shear (for local shear, strength is reduced to two-thirds).
- The load is vertical and central.
Failure mechanism
q_u ____________
| I |
II /\ /\ II
III / \ / \ III
Under the footing, zone I is an elastic (triangular) wedge with base angles . Zone II is a radial shear zone bounded by a logarithmic spiral. Zone III is a passive Rankine zone.
Derivation (outline)
Considering vertical equilibrium of the wedge: , where is the cohesive force on each inclined face, the weight of the wedge, and the passive resistance from zones II and III (made of three parts, due to , and ). This gives
For other shapes: square ; circular . depend only on (e.g. for : ). For local shear use , .
✓ Answer checked by Claude Sonnet 5.5
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