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Trench bottom heave safety factor

Short answer

Arching is pressure transfer from yielding to stationary soil via shear. For deep clay, factor of safety against heave FS = 5.7c/(γH − √2 cH/B) = 2.46. With hard rock at 2.5 m below base, FS = 5.7c/(γH − cH/T) = 4.99.

What is arching effect in soils? A long 5 m wide and 10 m high vertical trench has to be constructed in a deep deposit of cohesive soil with c=35 kN/m2c = 35\ \text{kN/m}^2 and γ=18 kN/m3\gamma = 18\ \text{kN/m}^3. The safety of the bottom of trench against heave is to be checked before protecting the trench walls using sheet piles. If the excavation is to be completed rapidly, determine the factor of safety against bottom heave. What will be the factor of safety if a hard rock is present at 2.5 m from the bottom of the trench?

Arching effect

Arching is the transfer of pressure from a yielding part of a soil mass to the adjacent stationary parts through the shear resistance of the soil. The pressure on the yielding part decreases and that on the stationary part increases (Terzaghi's trap door experiment).

Factor of safety against bottom heave (Terzaghi)

Rapid excavation means undrained conditions, so ϕu=0\phi_u = 0 and c=cu=35c = c_u = 35 kN/m2^2. The heave is checked as a bearing failure of the base under the weight of soil beside the cut, resisted by shear on vertical planes. The bearing capacity of the base is taken as 5.7c5.7c.

(a) Deep clay (no hard layer; T≥0.7BT \ge 0.7B): the width of the failing strip is B′=B/2=0.7BB' = B/\sqrt2 = 0.7B:

FS=5.7cγH−2 cH/B=5.7×3518×10−2×35×10/5=199.581.01=2.46FS = \frac{5.7c}{\gamma H - \sqrt{2}\,cH/B} = \frac{5.7\times35}{18\times10 - \sqrt2\times35\times10/5} = \frac{199.5}{81.01} = 2.46

(b) Hard rock 2.5 m below the base: here T=2.5 m<0.7B=3.5T = 2.5\ \text{m} < 0.7B = 3.5 m, so the failure zone is limited by the rock and B′=T=2.5B' = T = 2.5 m:

FS=5.7cγH−cH/T=199.5180−35×10/2.5=199.540.0=4.99FS = \frac{5.7c}{\gamma H - cH/T} = \frac{199.5}{180 - 35\times10/2.5} = \frac{199.5}{40.0} = 4.99

Answer: FS=2.46FS = 2.46 for deep clay. This is above the usual minimum of about 1.5, so the base is safe against heave, although the margin is modest. With the rock 2.5 m below the trench bottom, FS=4.99FS = 4.99, which is more than adequate.

✓ Answer checked by Claude Sonnet 5.5

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