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- 2070 Chaitra · 6 marks
Normal definition; approximation conditions
Short answer
Normal distribution: continuous with pdf f(x)=(1/(σ√(2π)))e^(−(x−μ)²/(2σ²)). Binomial approximation requires large n, np≥5, nq≥5, and continuity correction. Poisson approximation needs λ≥10, also with continuity correction.
Define normal distribution. Give the condition for normal approximation of Binomial distribution and Poisson distribution.
Normal distribution: a continuous random variable X is normally distributed with mean μ and standard deviation σ if its pdf is
f(x) = (1 / (σ√(2π))) · e^(−(x − μ)² / (2σ²)), −∞ < x < ∞
written X ~ N(μ, σ²). Its curve is a symmetric bell shape, centred at μ, with mean = median = mode = μ, total area 1, and points of inflection at μ ± σ.
Normal approximation to the Binomial
If X ~ B(n, p), then for large n it is approximated by N(μ = np, σ² = npq) with q = 1 − p.
Conditions:
- n is large (n ≥ 30 is commonly used), and
- p is not too close to 0 or 1, so that np ≥ 5 and nq ≥ 5 (some books use 10).
Use the continuity correction: P(X = a) ≈ P(a − 0.5 < X < a + 0.5), and z = (x ± 0.5 − np)/√(npq).
Normal approximation to the Poisson
If X ~ Poisson(λ), then for large λ it is approximated by N(μ = λ, σ² = λ).
Condition:
- λ is large, commonly λ ≥ 10 (some books accept λ > 5), and the continuity correction is applied: z = (x ± 0.5 − λ)/√λ.
✓ Answer checked by Claude Sonnet 5.5
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