- 2070 Chaitra · 3+3 marks
SD of marks; effect of adding one
Short answer
SD = √(Σfx²/N − (Σfx/N)²) = 1.774 marks. Adding 1 to every mark shifts the mean but does not alter deviations; the SD stays 1.774.
Calculate the standard deviation from the following data regarding marks obtained by students in a test:
| Marks | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
|---|---|---|---|---|---|---|---|---|---|
| No. of Students | 32 | 41 | 57 | 98 | 123 | 83 | 46 | 17 | 3 |
| What will be the value of standard deviation if the marks obtained by each of the students are increased by one? |
Formula for a frequency distribution: σ = √[ Σfx²/N − (Σfx/N)² ].
| Marks x | f | fx | fx² |
|---|---|---|---|
| 1 | 32 | 32 | 32 |
| 2 | 41 | 82 | 164 |
| 3 | 57 | 171 | 513 |
| 4 | 98 | 392 | 1568 |
| 5 | 123 | 615 | 3075 |
| 6 | 83 | 498 | 2988 |
| 7 | 46 | 322 | 2254 |
| 8 | 17 | 136 | 1088 |
| 9 | 3 | 27 | 243 |
| Total | 500 | 2275 | 11,925 |
Mean = 2275/500 = 4.55
σ² = 11,925/500 − (4.55)² = 23.85 − 20.7025 = 3.1475
σ = √3.1475 = 1.774
(With divisor N − 1 the SD would be 1.776.)
Effect of adding one to every mark
Adding a constant to every observation shifts the mean by the same constant but does not change the distances from the mean. So the SD is unchanged: σ(x + 1) = σ(x). The new mean would be 5.55.
Answer: SD = 1.774 marks; after increasing each mark by one, the SD is still 1.774.
✓ Answer checked by Claude Sonnet 5.5
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