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Indeterminacy: frame with hinge and truss

Short answer

(i) Frame: static indeterminacy = 8, kinematic = 22 (12 if members inextensible). (ii) Truss: static indeterminacy = 4, kinematic = 17.

Obtain the degree of static and kinematic indeterminacies for the given structures. [Figure: (i) a two-bay, two-storey frame with an internal hinge, supports hinged/fixed/roller as drawn; (ii) a multi-panel truss with double diagonals, hinged at one end and roller at the other.]

(i) Two-bay, two-storey frame with an internal hinge

Reading of the figure: three column lines over two storeys with floor beams at two levels. Supports: one fixed, one hinged, one roller; one internal hinge.

j=9, m=10 (6 columns+4 beams), r=3+2+1=6, c=1j = 9,\ m = 10\ (6\ \text{columns} + 4\ \text{beams}),\ r = 3 + 2 + 1 = 6,\ c = 1

  • Static: Ds=3(10)+6−3(9)−1=8D_s = 3(10) + 6 - 3(9) - 1 = 8 (external 6−3=36-3 = 3; internal 3×2 closed loops−1=53 \times 2\ \text{closed loops} - 1 = 5).
  • Kinematic, axial deformation allowed: Dk=3(9)−6+1=22D_k = 3(9) - 6 + 1 = 22.
  • Kinematic, inextensible members: Dk=22−10=12D_k = 22 - 10 = 12.

(ii) Truss with double diagonals

Reading of the figure: four panels with top and bottom chords, five verticals and two diagonals in each panel (X-bracing). Hinge at one end, roller at the other.

j=10, m=4+4+5+8=21, r=3j = 10,\ m = 4 + 4 + 5 + 8 = 21,\ r = 3

  • Static: Ds=m+r−2j=21+3−20=4D_s = m + r - 2j = 21 + 3 - 20 = 4 (external 0, internal 4, one for each X-panel).
  • Kinematic: Dk=2j−r=20−3=17D_k = 2j - r = 20 - 3 = 17.

Answer: (i) Ds=8D_s = 8, Dk=22D_k = 22 (12 if inextensible); (ii) Ds=4D_s = 4, Dk=17D_k = 17.

✓ Answer checked by Claude Opus 5.5 (high effort)

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