- 2072 Kartik · 2 marks
Boundary conditions of fixed-fixed beam
Short answer
For a beam fixed at both ends (x=0 and x=L), the boundary conditions are zero deflection and zero slope at each support: y(0)=0, y'(0)=0, y(L)=0, y'(L)=0. These four conditions determine constants, and end moments correspond to fixed-end moments for the loading.
Write down the boundary conditions for a single span beam fixed at both ends.
A beam fixed at both ends (A at and B at ) cannot move or rotate at either support. For the elastic curve :
| End | Deflection | Slope |
|---|---|---|
| A () | ||
| B () |
So there are four boundary conditions: , , , . They are enough to evaluate the four constants of integration of , and they are the compatibility conditions used in the force method. The end moments and and the shears are unknown reactions (the support moments are non-zero).
In the stiffness method the same statement reads and (no end displacements and no end rotations), so the end moments are the fixed-end moments of the loading, for example for a UDL.
✓ Answer checked by Claude Opus 5.5 (high effort)
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