- 2078 Kartik · 2+3 marks
Flexibility, stiffness coefficient; suitable method
Short answer
Flexibility coefficient f_ij is displacement at i due to unit force at j; stiffness coefficient k_ij is force at i for unit displacement at j with others fixed. Displacement method is more suitable: the frame has fewer unknowns (4 vs 5 redundants) after modified stiffness for the hinged column, well-suited for slope-deflection.
Define flexibility and stiffness coefficient. For the given frame, which of the methods, force or displacement, is suitable? Give your reasons. [Figure: single-storey frame with a middle column that is hinged at its base.]
Flexibility coefficient
The flexibility coefficient is the displacement at coordinate due to a unit force applied at coordinate (all other coordinates unloaded). Its unit is m/kN (or rad/kNm). The flexibility matrix relates displacements and forces: .
Stiffness coefficient
The stiffness coefficient is the force required at coordinate to produce a unit displacement at coordinate while all other coordinates are held fixed. The stiffness matrix gives , and .
Suitable method
Read the figure as a single-storey, two-bay frame with fixed outer bases and a hinged base under the middle column: .
(inextensible) (three top-joint rotations, one base-hinge rotation, one sway).
Because the base of the middle column is hinged, its far-end rotation can be removed with the modified stiffness . The effective unknowns of the displacement method fall to 4, compared with 5 redundants in the force method.
Displacement method is more suitable because
- it has fewer unknowns (4 against 5);
- the frame is a regular framed system with several rotating joints and sway, which suits slope-deflection or moment distribution well;
- the force method needs a stable released structure and many moment diagrams for 5 redundants, which is long hand work.
✓ Answer checked by Claude Opus 5.5 (high effort)
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