- 2070 Asar · 10 marks
Force method: reactions at D, frame with 110 kN
Short answer
Using force method with hinge D released, horizontal reaction H_D = 33.72 kN (left), vertical reaction V_D = 126.32 kN (up). Fixed end A: H_A = 76.28 kN left, V_A = 23.68 kN up, M_A = 183.40 kNm anticlockwise.
Determine horizontal and vertical reactions at support D of the frame shown in figure below using the force method. [Figure: portal frame ABCD; beam BC (2EI) of 5 m with 30 kN/m UDL; columns AB and CD (EI) 4 m high; 110 kN horizontal at B; A fixed, D hinged.]
Reading of the figure: portal frame ABCD, columns AB and CD are 4 m high (), the beam BC is 5 m long () with 30 kN/m, a 110 kN horizontal load acts at B (towards C), A is fixed and D is hinged.
. Release the hinge at D and take = horizontal reaction () and = vertical reaction (). The primary structure is the cantilever fixed at A.
110 kN-> B ============ C 30 kN/m
| |
| 4 m | 4 m
| |
///A o D (hinge)
Moment diagrams in the primary structure (+ tension on the inner face)
- : in the beam, kNm at B (UDL resultant ) falling parabolically to 0 at C; in the column AB it varies linearly from at B to kNm at A.
- (unit horizontal force at D): CD from 0 to 4, beam constant 4, column AB from 4 at B down to 0 at A.
- (unit vertical force at D): beam from 5 at B to 0 at C, column AB constant 5.
Flexibility coefficients (in units)
Compatibility
Final bending moments (kNm)
| Section | ||||
|---|---|---|---|---|
| A | -815.00 | 0.00 | 5.00 | -183.40 |
| B (column) | -375.00 | 4.00 | 5.00 | 121.72 |
| mid BC | -93.75 | 4.00 | 2.50 | 87.17 |
| C (beam) | 0.00 | 4.00 | 0.00 | -134.88 |
| D | 0.00 | 0.00 | 0.00 | 0.00 |
Maximum sagging moment in BC: 131.07 kNm at 0.79 m from B.
Reactions
- D (hinge): kN (towards the left), kN ()
- A (fixed): kN (towards the left), kN (), kNm (anticlockwise)
Check: : ; : kN.
Answer: at the hinged support D, the horizontal reaction is kN (towards the left) and the vertical reaction is kN (upward).
✓ Answer checked by Claude Opus 5.5 (high effort)
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