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Rural village demand for 2092 BS, incremental method

Short answer

Use incremental increase over 2.4 decades: design population in 2092 is 22,366. With domestic 45 lpcd and given institutional, livestock, and 15% losses, total water requirement is 1,181 m3/day, about 13.7 l/s.

Estimate the total water requirement for a rural village for the year 2092 BS by forecasting the population by incremental increase method with the following census data.

Year (BS)201820282038204820582068
Population720081009300110001300016000

There are 3 schools (350 day and 50 boarder scholars), livestock (5000 chickens, 1500 goats and 60 cows), 2 health posts with 10 beds capacity and other offices with 100 staffs altogether. Neglect the fire demand for rural area.

The design year is 2092 BS. The last census is 2068, so n=(2092−2068)/10=2.4n = (2092-2068)/10 = 2.4 decades.

Population by incremental increase method

Increase per decade: 900, 1,200, 1,700, 2,000, 3,000; incremental increase: 300, 500, 300, 1,000. xˉ=1,760.00\bar x = 1{,}760.00, yˉ=525.00\bar y = 525.00

P2092=Pn+nxˉ+n(n+1)2yˉ=16,000+2.4(1,760.00)+2.4(3.4)2(525.00)=22,366P_{2092} = P_n + n\bar x + \frac{n(n+1)}{2}\bar y = 16{,}000 + 2.4(1{,}760.00) + \frac{2.4(3.4)}{2}(525.00) = 22{,}366

Water demand

Design values assumed (Nepal rural water supply practice): domestic 45 lpcd (public taps); day scholar 5 l/d; boarder 45 l/d; office staff 45 l/d; big animal (cow, buffalo) 45 l/d; small animal (goat, pig) 5 l/d; poultry 0.2 l/d; losses and wastage 15% of net demand. Health post beds are taken at 100 l/bed/day. The 3 schools have 350 day scholars and 50 boarders in total, and the 2 health posts have 10 beds in total. Fire demand is neglected.

DemandQuantityRateDemand (l/day)
Domestic (45 lpcd)22,36645 l/c/d1,006,470
Day scholars3505 l/c/d1,750
Boarders5045 l/c/d2,250
Chickens5,0000.2 l/d1,000
Goats1,5005 l/d7,500
Cows6045 l/d2,700
Health posts (10 beds in total)10100 l/bed/d1,000
Office staff10045 l/staff4,500
Net demand1,027,170

Losses and wastage =15%= 15\% of net demand =154,076= 154{,}076 l/day

Qavg=1,027,170+154,076=1,181,246 l/day=1,181.25 m3/day=13.67 l/sQ_{avg} = 1{,}027{,}170 + 154{,}076 = 1{,}181{,}246\ \text{l/day} = 1{,}181.25\ \mathrm{m^3/day} = 13.67\ \text{l/s}

Answer: Design population (2092 BS) = 22,366; total water requirement = 1,181 m3^3/day (13.7 l/s).

✓ Answer checked by Claude Opus 5.5 (high effort)

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