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Impounded reservoir, 6202 million L per month

Short answer

Monthly inflows are converted to volumes. The analytical mass curve method finds the largest cumulative deficit of 20.40×10^6 m³ at the end of July. Required reservoir capacity ≈ 20.40 million m³ (20,405 ML).

The city has an average water demand of 6202 million liters per month. Calculate the capacity of the impounded reservoir. The flow in the river is shown below.

MonthInflow (m3^3/s)
January2.97
February1.99
March1.00
April0.00
May0.51
June1.00
July2.00
August3.00
September4.00
October5.00
November4.00
December2.80

Convert the monthly flows to volumes (V=Q×86400×daysV = Q\times86400\times\text{days}) and apply the mass curve (analytical) method. Demand D=6202 ML/month=6.202 Mm3D = 6202\ \text{ML/month} = 6.202\ \text{Mm}^3 per month (1 ML = 1000 m3^3).

Monthly inflow volumes

MonthDaysInflow (m3/s)Volume (Mm3)
Jan312.977.955
Feb281.994.814
Mar311.002.678
Apr300.000.000
May310.511.366
Jun301.002.592
Jul312.005.357
Aug313.008.035
Sep304.0010.368
Oct315.0013.392
Nov304.0010.368
Dec312.807.500

Total inflow =74.42= 74.42 Mm3^3; total demand =12×6.202=74.42= 12\times6.202 = 74.42 Mm3^3. The two are equal, so the reservoir must carry the whole yearly regulation.

Cumulative deficit (reservoir full at the start of the deficit period)

MonthInflow (Mm3)Demand (Mm3)Surplus/deficitCumulative deficit
Feb4.8146.202-1.388-1.388
Mar2.6786.202-3.524-4.911
Apr0.0006.202-6.202-11.113
May1.3666.202-4.836-15.949
Jun2.5926.202-3.610-19.559
Jul5.3576.202-0.845-20.405

The inflow is below the demand from Feb to Jul; the cumulative deficit is largest at the end of Jul.

Answer: Capacity of the impounded reservoir = 20.40 million m3^3 (≈20,405\approx 20{,}405 ML).

✓ Answer checked by Claude Opus 5.5 (high effort)

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