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Multi-tone AM: spectrum, bandwidth, power efficiency

Short answer

Spectrum: carrier 50 V at fc = 159.155 kHz, sideband pairs at ±500 Hz (7.5 V) and ±400 Hz (5 V). Bandwidth = 2 × 500 Hz = 1 kHz. Power efficiency η = (0.3²+0.2²)/(2+0.3²+0.2²) = 0.13/2.13 = 6.10%.

An amplitude modulated wave is given by s(t) = 50(1 + 0.3cos3141.60t + 0.2cos2513.28t)cos10⁶t i) Draw the amplitude spectrum of s(t) ii) Determine the bandwidth of s(t) iii) Calculate the power efficiency

Compare with s(t)=Ac[1+μ1cos⁡ω1t+μ2cos⁡ω2t]cos⁡ωcts(t) = A_c[1 + \mu_1\cos\omega_1t + \mu_2\cos\omega_2t]\cos\omega_ct:

QuantityValue
AcA_c50 V
μ1\mu_1, ω1\omega_10.3, 3141.60 rad/s → f1=500f_1 = 500 Hz
μ2\mu_2, ω2\omega_20.2, 2513.28 rad/s → f2=400f_2 = 400 Hz
ωc\omega_c10610^6 rad/s → fc=159.155f_c = 159.155 kHz

i) Amplitude spectrum

Expanding:

s(t)=50cos⁡ωct+7.5cos⁡(ωc±3141.6)t+5cos⁡(ωc±2513.28)t\begin{aligned} s(t) = {} & 50\cos\omega_ct + 7.5\cos(\omega_c \pm 3141.6)t + 5\cos(\omega_c \pm 2513.28)t \end{aligned}

(Side amplitudes μAc/2\mu A_c/2: 0.3×50/2=7.50.3 \times 50/2 = 7.5 V; 0.2×50/2=50.2 \times 50/2 = 5 V.)

ω (rad/s)fAmplitude
996 858.4158.655 kHz7.5 V
997 486.7158.755 kHz5 V
1 000 000159.155 kHz50 V
1 002 513.3159.555 kHz5 V
1 003 141.6159.655 kHz7.5 V
  A(V)
  50 |                  |
     |                  |
 7.5 |   |              |              |
   5 |   |     |        |        |     |
     +---+-----+--------+--------+-----+---> f
       fc-500 fc-400    fc    fc+400 fc+500 (Hz)
                   fc = 159.155 kHz

ii) Bandwidth

B=2fmax=2×500=1000 Hz (=6283.2 rad/s)B = 2f_{max} = 2 \times 500 = 1000\ \text{Hz}\ (= 6283.2\ \text{rad/s})

iii) Power efficiency

μt2=μ12+μ22=0.09+0.04=0.13\mu_t^2 = \mu_1^2 + \mu_2^2 = 0.09 + 0.04 = 0.13 η=μt22+μt2=0.132.13=0.0610=6.10%\eta = \frac{\mu_t^2}{2 + \mu_t^2} = \frac{0.13}{2.13} = 0.0610 = 6.10\%

Check with powers (1 Ω): Pc=1250P_c = 1250 W, PSB=1250×0.13/2=81.25P_{SB} = 1250 \times 0.13/2 = 81.25 W, Pt=1331.25P_t = 1331.25 W, η=81.25/1331.25=6.10%\eta = 81.25/1331.25 = 6.10\%.

Answer: B=1B = 1 kHz; η=6.10%\eta = 6.10\%.

✓ Answer checked by Claude Opus 5.5 (high effort)

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