- 2073 Bhadra (CS I) · 4+3+3 marks
Multi-tone AM: spectrum, bandwidth, power efficiency
Short answer
Spectrum: carrier 50 V at fc = 159.155 kHz, sideband pairs at ±500 Hz (7.5 V) and ±400 Hz (5 V). Bandwidth = 2 × 500 Hz = 1 kHz. Power efficiency η = (0.3²+0.2²)/(2+0.3²+0.2²) = 0.13/2.13 = 6.10%.
An amplitude modulated wave is given by s(t) = 50(1 + 0.3cos3141.60t + 0.2cos2513.28t)cos10⁶t i) Draw the amplitude spectrum of s(t) ii) Determine the bandwidth of s(t) iii) Calculate the power efficiency
Compare with :
| Quantity | Value |
|---|---|
| 50 V | |
| , | 0.3, 3141.60 rad/s → Hz |
| , | 0.2, 2513.28 rad/s → Hz |
| rad/s → kHz |
i) Amplitude spectrum
Expanding:
(Side amplitudes : V; V.)
| ω (rad/s) | f | Amplitude |
|---|---|---|
| 996 858.4 | 158.655 kHz | 7.5 V |
| 997 486.7 | 158.755 kHz | 5 V |
| 1 000 000 | 159.155 kHz | 50 V |
| 1 002 513.3 | 159.555 kHz | 5 V |
| 1 003 141.6 | 159.655 kHz | 7.5 V |
A(V)
50 | |
| |
7.5 | | | |
5 | | | | | |
+---+-----+--------+--------+-----+---> f
fc-500 fc-400 fc fc+400 fc+500 (Hz)
fc = 159.155 kHz
ii) Bandwidth
iii) Power efficiency
Check with powers (1 Ω): W, W, W, .
Answer: kHz; .
✓ Answer checked by Claude Opus 5.5 (high effort)
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