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Analog communication block diagram; FDM of three signals

Short answer

An analog communication system comprises source, modulator, channel, demodulator, and destination. In FDM, three 4 kHz bandwidth-limited signals modulate separate carriers (e.g., 100, 105, 110 kHz) using SSB and are summed; bandpass filters and demodulators recover them at the receiver.

Discuss a block diagram of an analog communication system. Explain FDM system with neat diagrams, assuming three different message signals are to be transmitted simultaneously.

Block diagram of an analog communication system

An analog communication system carries a continuously varying message from a source to a user over a channel. The message is first converted to an electrical signal and then modulated onto a carrier.

 [Information source]
         |
 [Input transducer]
         |
 [Transmitter (modulator)]
         |
 [Channel] <---- noise, interference
         |
 [Receiver (demodulator)]
         |
 [Output transducer] --> user
  • Information source and input transducer: produce the message, e.g. speech converted to voltage by a microphone.
  • Transmitter: amplifies, filters and modulates (AM/FM/PM) the message onto a carrier suited to the channel, then power-amplifies it.
  • Channel: a wire, coaxial cable, optical fibre or free space. It attenuates and distorts the signal and adds noise.
  • Receiver: selects the wanted signal, amplifies it, demodulates it and filters it to recover the message.
  • Output transducer: a loudspeaker or display that turns the electrical signal back into its original form.

FDM system for three message signals

Assume three messages m1(t),m2(t),m3(t)m_1(t), m_2(t), m_3(t), each band-limited to W=4W = 4 kHz, and SSB modulation with carriers fc1=100f_{c1} = 100 kHz, fc2=105f_{c2} = 105 kHz and fc3=110f_{c3} = 110 kHz (upper sideband kept, 1 kHz guard band).

 TRANSMITTER
 m1 ->[LPF]->[SSB mod fc1]->[BPF1]--+
 m2 ->[LPF]->[SSB mod fc2]->[BPF2]--+-->(+)--> channel
 m3 ->[LPF]->[SSB mod fc3]->[BPF3]--+

 RECEIVER
          +->[BPF1]->[demod fc1]->[LPF]-> m1
 channel -+->[BPF2]->[demod fc2]->[LPF]-> m2
          +->[BPF3]->[demod fc3]->[LPF]-> m3

Spectrum of the multiplexed signal:

  |  m1  |g|  m2  |g|  m3  |
  100    104 105  109 110   114  kHz
  |<--------- 14 kHz ---------->|

Working:

  1. LPFs band-limit each message to WW.
  2. Each message modulates its own carrier. BPFs keep one sideband, so each signal sits in its own band.
  3. The adder combines them. The composite signal (bandwidth 3W3W + guard bands = 14 kHz here) is sent over one channel.
  4. At the receiver, BPFs centred on each band separate the three signals. Coherent demodulators with fc1,fc2,fc3f_{c1}, f_{c2}, f_{c3} and LPFs recover m1,m2,m3m_1, m_2, m_3.

Guard bands and good filters prevent crosstalk between the channels.

✓ Answer checked by Claude Opus 5.5 (high effort)

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