- 2077 Chaitra (CS I) · 8 marks
Armstrong FM transmitter numerical
Short answer
After ×65: 13 MHz, deviation 1.625 kHz. Mixing with 10.8 MHz yields 2.2 MHz. After ×50: maximum deviation = 81.25 kHz, carrier frequency = 110 MHz.
For a given Armstrong FM transmitter, the NBFM output has a frequency of 200 kHz and frequency deviation of 25 Hz. This signal is then frequency multiplied by 65 and passed through mixer of oscillation frequency 10.8 MHz. The resulting signal is then fed to a frequency multiplier with n = 50. Calculate the maximum frequency deviation and the valid carrier frequency of the WBFM for commercial use. Draw the necessary diagram.
In the Armstrong method, frequency multipliers multiply both carrier frequency and deviation; the mixer shifts the carrier frequency but leaves the deviation unchanged.
Diagram
NBFM x65 Mixer x50
200 kHz -->[n1]-->13 MHz-->[X]-->2.2M-->[n2]--> WBFM
df=25 Hz df=1625 Hz ^ df=1625 110 MHz
| df=81.25k
[Osc 10.8 MHz]
Step 1: after first multiplier (n₁ = 65)
Step 2: mixer with 10.8 MHz
The mixer gives MHz, i.e. 2.2 MHz (difference) or 23.8 MHz (sum). Deviation stays 1625 Hz.
Step 3: second multiplier (n₂ = 50)
Valid carrier frequency
The sum term gives 1190 MHz (UHF), which is far outside the VHF FM broadcast range and is rejected by filtering after the mixer. The difference term is the usable one, giving
Answer: maximum frequency deviation Δf = 81.25 kHz; valid WBFM carrier f_c = 110 MHz (from the 2.2 MHz difference output).
Note: 110 MHz lies just above the 88–108 MHz broadcast band and 81.25 kHz is slightly above the 75 kHz standard, so in practice the oscillator frequency or multiplier would be adjusted slightly; with the given data, 110 MHz is the only practical (VHF) choice.
✓ Answer checked by Claude Opus 5.5 (high effort)
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