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- 2070 Chaitra (CS II) · 6 marks
(7,4) cyclic code g(x) = 1 + x + x³ for 1011
Short answer
Non-systematic: multiply m(x)=1+x²+x³ by g(x)=1+x+x³ modulo 2, giving codeword 1111111. Systematic: divide x³m(x) by g(x); remainder 1 yields parity bits 100, codeword 1001011.
The generator polynomial of a (7,4) cyclic code is g(x) = 1 + x + x³. Find the code for the message vector 1011 in a non-systematic and systematic form.
A cyclic code is a linear block code in which every cyclic shift of a codeword is also a codeword. An cyclic code is generated by a polynomial of degree that divides :
- Non-systematic encoding: ; message bits are not visible directly in the codeword.
- Systematic encoding: ; the message appears unchanged and the remainder gives the parity bits.
Given , , . Convention (Haykin): message in ascending powers of :
All arithmetic is modulo 2.
Non-systematic form
( appears three times, leaving .)
Non-systematic code vector = 1111111
Systematic form
- Divide by :
x^3 + x^2 + x + 1
---------------------------
x^3+x+1 ) x^6 + x^5 + x^3
x^6 + x^4 + x^3
-------------------------
x^5 + x^4
x^5 + x^3 + x^2
-----------------------
x^4 + x^3 + x^2
x^4 + x^2 + x
-------------------
x^3 + x
x^3 + x + 1
-----------------
1
- Remainder , parity bits .
- .
Check: quotient . Valid.
Systematic code vector = 100 1011
| Form | Code vector |
|---|---|
| Non-systematic | 1111111 |
| Systematic | 1001011 |
✓ Answer checked by Claude Opus 5.5 (high effort)
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