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Design goals of digital modulation; coherent BPSK

Short answer

Key design goals are maximizing data rate and interference robustness while minimizing error probability, power, bandwidth, and circuit complexity. Coherent BPSK uses antipodal signals ±√(E_b) φ1(t), represented by points ±√E_b on one axis. The modulator applies polar NRZ to a product modulator; the demodulator correlates with a local carrier and decides with a zero threshold.

What are the design goals of digital modulation techniques? Explain coherent binary PSK modulation technique with its signal space diagram, modulator and demodulator.

Design goals of digital modulation

A good digital modulation scheme aims to:

  1. Maximise data rate for the available channel.
  2. Minimise probability of symbol/bit error for a given Eb/N0E_b/N_0.
  3. Minimise transmitted power (important for battery and satellite systems).
  4. Minimise channel bandwidth (high spectral efficiency, bits/s/Hz).
  5. Maximise resistance to interference and fading.
  6. Minimise circuit complexity and cost.

These goals conflict (e.g. higher-level schemes save bandwidth but need more power), so the choice is a trade-off.

Coherent binary PSK

In BPSK the carrier phase is shifted by 180∘180^\circ between the two symbols:

s1(t)=2EbTbcos⁡2πfct  (symbol 1),s2(t)=−2EbTbcos⁡2πfct  (symbol 0)s_1(t)=\sqrt{\frac{2E_b}{T_b}}\cos 2\pi f_ct\ \ (\text{symbol }1),\qquad s_2(t)=-\sqrt{\frac{2E_b}{T_b}}\cos 2\pi f_ct\ \ (\text{symbol }0)

for 0≤t≤Tb0\le t\le T_b, where EbE_b is the bit energy and fc=nc/Tbf_c=n_c/T_b. The two signals are antipodal.

Signal space diagram

Only one orthonormal basis function is required:

ϕ1(t)=2Tbcos⁡2πfct,0≤t≤Tb\phi_1(t)=\sqrt{\frac{2}{T_b}}\cos 2\pi f_ct,\quad 0\le t\le T_b

so s1(t)=Eb ϕ1(t)s_1(t)=\sqrt{E_b}\,\phi_1(t) and s2(t)=−Eb ϕ1(t)s_2(t)=-\sqrt{E_b}\,\phi_1(t). The coordinates are

s11=∫0Tbs1(t)ϕ1(t)dt=+Eb,s21=−Ebs_{11}=\int_0^{T_b}s_1(t)\phi_1(t)dt=+\sqrt{E_b},\qquad s_{21}=-\sqrt{E_b}
        Z2 (decide 0)  |  Z1 (decide 1)
   s2                   |                   s1
 ---*-------------------+-------------------*---> phi1
 -sqrt(Eb)              0              +sqrt(Eb)
                 decision boundary

Distance d12=2Ebd_{12}=2\sqrt{E_b}. The decision boundary is the midpoint, x1=0x_1=0.

Modulator

 binary data -->[Polar NRZ level encoder]--> b(t)
                 1 -> +sqrt(Eb), 0 -> -sqrt(Eb)
                                    |
                                   (X)<-- phi1(t)
                                    |
                                 BPSK s(t)

The level encoder converts 1 and 0 to +Eb+\sqrt{E_b} and −Eb-\sqrt{E_b}; the product modulator multiplies by ϕ1(t)\phi_1(t). The result is a constant-envelope carrier whose phase flips with the data.

Demodulator (coherent detector)

 x(t) -->(X)-->[ integral 0..Tb ]--x1--> [Decision device]
          ^                              x1 > 0 -> 1
        phi1(t)                          x1 < 0 -> 0
   (from carrier and bit-timing recovery)
  1. The received signal x(t)=si(t)+w(t)x(t)=s_i(t)+w(t) is multiplied by a locally generated ϕ1(t)\phi_1(t), exactly in phase with the transmitted carrier.
  2. The integrator over one bit gives x1=±Eb+nx_1=\pm\sqrt{E_b}+n, where nn is Gaussian with variance N0/2N_0/2.
  3. The decision device compares x1x_1 with zero.

Performance

Pe=12 erfc(EbN0)P_e=\frac12\,\text{erfc}\left(\sqrt{\frac{E_b}{N_0}}\right)

BPSK has the lowest error probability of all binary schemes (3 dB better than coherent BFSK). Its null-to-null bandwidth is 2/Tb2/T_b. Its drawback is the need for an accurate coherent reference (Costas or squaring loop).

✓ Answer checked by Claude Opus 5.5 (high effort)

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