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- 2074 Chaitra (CS II) · 2+10 marks
Ergodic process; WSS random signals through LTI
Short answer
An ergodic process has time averages equal to ensemble averages, so mean and autocorrelation can be measured from a single record. Passing WSS X(t) through LTI h(t) gives output Y with mean m_X H(0) and autocorrelation R_Y(τ)=h(τ)*h(-τ)*R_X(τ), keeping Y WSS; output PSD is |H(f)|²S_X(f).
What do you mean by Ergodic Stochastic Process? Explain with necessary derivation passage of wide-sense random signals through a LTI.
Ergodic stochastic process
A stationary random process is ergodic if its time averages, taken over one long sample function, equal its ensemble averages, taken across all sample functions at one instant:
Ergodicity allows the mean (DC value), power and autocorrelation of noise to be measured from a single long record. An ergodic process must be stationary, but a stationary process need not be ergodic.
Passage of WSS random signals through an LTI system
Let a WSS process (mean , autocorrelation , PSD ) be applied to a stable LTI system with impulse response and :
X(t) (WSS) +--------------+ Y(t)
------------->| h(t) , H(f) |------------->
R_X, S_X +--------------+ R_Y, S_Y
1. Mean of output. Expectation and integration can be interchanged:
2. Autocorrelation of output.
because is WSS, its autocorrelation depends only on the time difference . The result depends only on , not on :
3. Mean-square value is finite and constant.
Since the mean is constant and the autocorrelation depends only on , is also wide-sense stationary.
4. Output PSD. Taking the Fourier transform of (, ):
and the output power is . The phase of has no effect on the output PSD.
Example (white noise through RC low-pass filter). , , output power .
Cross-correlation: ; for white-noise input, , so correlating output with input measures .
✓ Answer checked by Claude Opus 5.5 (high effort)
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