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Hilbert transformation; properties of LTI system

Short answer

The Hilbert transform shifts positive-frequency phase by −90° and negative by +90° without altering amplitudes, used for SSB and analytic signals. LTI systems obey superposition and time invariance; key properties include causality (h(t)=0 for t<0), stability (∫|h|dt finite), and eigenfunction property where sinusoids only change amplitude and phase, no new frequencies.

Define Hilbert transformation. State and explain the properties of LTI system.

Hilbert transformation

The Hilbert transform x^(t)\hat{x}(t) of a signal x(t)x(t) shifts the phase of all its positive-frequency components by −90∘-90^\circ and negative-frequency components by +90∘+90^\circ, leaving amplitudes unchanged:

x^(t)=1π∫−∞∞x(τ)t−τdτ=x(t)∗1πt,X^(f)=−j sgn(f) X(f)\hat{x}(t) = \frac{1}{\pi}\int_{-\infty}^{\infty}\frac{x(\tau)}{t-\tau}d\tau = x(t) * \frac{1}{\pi t}, \qquad \hat{X}(f) = -j\,\text{sgn}(f)\,X(f)

Example: cos⁡2πfct→sin⁡2πfct\cos 2\pi f_ct \to \sin 2\pi f_ct. It is used for SSB generation and for the analytic signal x+(t)=x(t)+jx^(t)x_+(t) = x(t) + j\hat x(t).

Properties of LTI systems

An LTI system is completely described by its impulse response h(t)h(t) (or transfer function H(f)H(f)), and y(t)=x(t)∗h(t)y(t) = x(t) * h(t).

  1. Linearity (superposition): ax1+bx2→ay1+by2a x_1 + b x_2 \to a y_1 + b y_2. Allows analysing a complex input as a sum of simple ones (e.g. sinusoids).
  2. Time invariance: x(t−t0)→y(t−t0)x(t - t_0) \to y(t - t_0); the system behaves the same at all times.
  3. Commutative: x∗h=h∗xx * h = h * x.
  4. Associative (cascade): (x∗h1)∗h2=x∗(h1∗h2)(x * h_1) * h_2 = x * (h_1 * h_2); two systems in cascade have h=h1∗h2h = h_1 * h_2 and H=H1H2H = H_1H_2.
  5. Distributive (parallel): x∗(h1+h2)=x∗h1+x∗h2x * (h_1 + h_2) = x * h_1 + x * h_2; parallel systems add.
  6. Causality: causal if h(t)=0h(t) = 0 for t<0t < 0.
  7. Stability (BIBO): stable if ∫∣h(t)∣dt<∞\int|h(t)|dt < \infty.
  8. Eigenfunction property: an input ej2πf0te^{j2\pi f_0t} gives H(f0)ej2πf0tH(f_0)e^{j2\pi f_0t}; sinusoids pass through with only gain and phase change, no new frequencies.

✓ Answer checked by Claude Opus 5.5 (high effort)

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