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Impulse response of matched filter
Short answer
Maximizing the output SNR at sampling instant T via the Schwarz inequality yields H_opt(f)=k G*(f) e^{-j2πfT}. The impulse response is h_opt(t)=k g(T-t), the time-reversed and delayed version of the input pulse, called the matched filter.
Derive the expression for the impulse response of a matched filter for a AWGN channel.
A matched filter is the linear filter that maximises the peak output signal-to-noise ratio at the sampling instant when a known pulse is received in additive white Gaussian noise (AWGN). It is used as the optimum detector in digital receivers.
Derivation
Consider a known pulse , , plus white Gaussian noise of power spectral density , applied to a linear time-invariant filter with impulse response and transfer function .
x(t) = g(t) + w(t) --> [ h(t) ] --> y(t) = go(t) + n(t)
|
sample at t = T
Signal output at the sampling instant:
Noise output power (white noise through ):
Peak pulse SNR to be maximised:
Schwarz inequality: for any ,
with equality only when . Put and :
Substituting into :
using Rayleigh's energy theorem .
Optimum filter: the maximum is reached when equality holds:
Impulse response: take the inverse Fourier transform:
So the impulse response of the optimum filter is the time-reversed and delayed (by ) version of the input signal, scaled by . Because it is "matched" to the signal, it is called the matched filter.
g(t) h(t) = g(T - t)
|\ /|
| \ / |
| \ / |
+---+-----> t +---+---+----> t
0 T 0 T
(flip about t = 0, then shift right by T)
Properties
- Maximum output SNR depends only on the signal energy, not on its shape.
- : the filter passes strongly where the signal spectrum is strong.
- The output is proportional to the autocorrelation of shifted by , peaking at ; hence a matched filter is equivalent to a correlator (multiply by and integrate over to ).
- The delay makes causal (zero for ).
Example
For a rectangular pulse , , the matched filter is for (an integrate-and-dump filter). The output is a triangle peaking at with value , and .
✓ Answer checked by Claude Opus 5.5 (high effort)
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