- 2080 Bhadra (CS II) · 8 marks
State and prove Nyquist sampling theorem
Short answer
A band-limited signal with max frequency W is uniquely determined by samples taken at fs ≥ 2W. Ideal sampling repeats the spectrum every fs; if fs ≥ 2W, copies do not overlap, and an ideal LPF recovers the original. Aliasing occurs if fs < 2W.
State and prove Nyquist sampling theorem.
Statement
A band-limited signal with no frequency components above Hz ( for ) is uniquely determined by its samples taken at uniform intervals , i.e. at a rate . It can be recovered exactly from the samples by an ideal low-pass filter of bandwidth .
The minimum rate is the Nyquist rate; is the Nyquist interval.
Proof
1. Ideal sampling. Multiply by a periodic impulse train:
2. Spectrum of the impulse train. It is periodic, with Fourier series coefficients :
3. Spectrum of the sampled signal. Multiplication in time is convolution in frequency:
So is repeated every Hz, scaled by .
f_s >= 2W (no overlap):
/\ /\ /\
/ \ / \ / \
--/----\----/----\----/----\---> f
-W 0 W fs-W fs 2fs
f_s < 2W: copies overlap -> aliasing
4. Condition for no overlap. The copy at occupies to . It does not overlap the baseband copy ( to ) if
5. Recovery. If , pass through an ideal LPF with for (any cut-off between and ):
so is recovered exactly.
6. Interpolation formula. With , the LPF impulse response is , so
Each sample is replaced by a sinc pulse and the sum rebuilds at all instants. This proves the theorem. If , the copies overlap (aliasing) and cannot be recovered; an anti-aliasing filter is therefore used before sampling.
✓ Answer checked by Claude Opus 5.5 (high effort)
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