- 2079 Chaitra · 3+5 marks
PCM, DPCM and DM comparison; SQNR of PCM
Short answer
PCM quantizes each sample with n bits; DPCM codes the prediction error with fewer bits; DM sends 1-bit sign of difference with oversampling. For uniform PCM, SQNR = (3P/mp²) 2^{2n}. For a full-scale sinusoid, SQNR_dB = 1.76 + 6.02n dB; each additional bit increases SQNR by about 6 dB.
Compare Pulse Code Modulation (PCM), Differential Pulse Code Modulation (DPCM) and Delta Modulation. Find the Signal to Quantization Noise ratio (SQNR) of Pulse Code Modulation (PCM).
Comparison of PCM, DPCM and DM
| Point | PCM | DPCM | DM |
|---|---|---|---|
| What is coded | Each sample value | Difference between sample and its prediction | Sign of difference only |
| Bits per sample | (e.g. 8) | Fewer than PCM (e.g. 4) | 1 |
| Sampling rate | (Nyquist) | Much higher than (oversampling) | |
| Predictor | None | Linear predictor | One-sample delay (accumulator) |
| Quantization noise | Granular, | Granular, smaller (prediction gain) | Granular + slope overload |
| SQNR | dB | PCM value + | |
| Bandwidth | Highest () | Less than PCM | Can be less, but needs high |
| Complexity | Moderate | Most complex | Simplest |
| Use | Telephony (64 kbps), CD | Speech, video coding | Simple voice links |
SQNR of PCM
Let have peak value and be quantized uniformly into levels.
Step size:
Noise power: the error is uniform in :
SQNR: with signal power ,
For a full-scale sinusoid, :
Each extra bit adds about 6 dB. Example: 8-bit PCM gives dB.
✓ Answer checked by Claude Opus 5.5 (high effort)
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