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Short note: Phase modulation

Short answer

Phase modulation varies the instantaneous carrier phase linearly with the message: s(t)=A_c cos(2π f_c t + k_p m(t)). The frequency deviation depends on dm/dt. For a tone, the modulation index β_p=k_p A_m is independent of f_m. PM has constant envelope and can be generated by differentiating the message before angle modulation.

Write a short note on phase modulation.

Phase modulation (PM) is angle modulation in which the instantaneous phase of the carrier varies linearly with the message signal, while the amplitude stays constant.

sPM(t)=Accos⁡[2πfct+kp m(t)]s_{PM}(t) = A_c\cos\left[2\pi f_c t + k_p\, m(t)\right]

where kpk_p is the phase sensitivity (rad/V).

Instantaneous frequency:

fi(t)=fc+kp2πdm(t)dtf_i(t) = f_c + \frac{k_p}{2\pi}\frac{dm(t)}{dt}

so in PM the frequency deviation depends on the rate of change of the message.

Single tone: for m(t)=Amcos⁡2πfmtm(t) = A_m\cos 2\pi f_m t,

s(t)=Accos⁡[2πfct+βpcos⁡2πfmt],βp=kpAms(t) = A_c\cos\left[2\pi f_c t + \beta_p\cos 2\pi f_m t\right], \qquad \beta_p = k_p A_m

The PM index βp\beta_p is independent of fmf_m, while the frequency deviation Δf=kpAmfm\Delta f = k_p A_m f_m increases with fmf_m.

Relation with FM:

  • PM of m(t)m(t) = FM of dmdt\frac{dm}{dt} (differentiator + FM modulator gives PM).
  • FM of m(t)m(t) = PM of ∫m dt\int m\,dt (integrator + phase modulator gives FM, used in Armstrong's method).

Features: constant envelope and power Ac2/2A_c^2/2; spectrum given by Bessel functions as in FM; bandwidth by Carson's rule 2(Δf+fm)2(\Delta f + f_m). PM can be demodulated by a phase detector (e.g. a PLL) or by an FM discriminator followed by an integrator. Digital forms of PM (BPSK, QPSK) are widely used in modern data communication.

✓ Answer checked by Claude Opus 5.5 (high effort)

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