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Single-tone FM in terms of Bessel coefficients

Short answer

The single-tone FM signal s(t)=A_c cos(ω_c t+β sin ω_m t) expands via Bessel functions to s(t)=A_c Σ_{n=-∞}^∞ J_n(β) cos[(ω_c+n ω_m)t]. The spectrum has a carrier at f_c (amplitude A_c J_0(β)) and infinite sidebands at f_c±n f_m with amplitudes A_c|J_n(β)|; total power remains constant.

Derive the expression for single tone modulated FM signal in terms of Bessel coefficients.

In frequency modulation, the instantaneous frequency of the carrier varies linearly with the message. For a single tone, the FM wave can be expanded with Bessel functions into a carrier and an infinite set of sidebands.

Instantaneous frequency and phase

Let m(t)=Amcos⁡ωmtm(t) = A_m\cos\omega_mt and c(t)=Accos⁡ωctc(t) = A_c\cos\omega_ct. The instantaneous frequency is

fi(t)=fc+kfm(t)=fc+kfAmcos⁡ωmt=fc+Δfcos⁡ωmtf_i(t) = f_c + k_fm(t) = f_c + k_fA_m\cos\omega_mt = f_c + \Delta f\cos\omega_mt

where kfk_f is the frequency sensitivity (Hz/V) and Δf=kfAm\Delta f = k_fA_m is the peak frequency deviation. The phase is

θi(t)=2π∫0tfi(τ) dτ=ωct+Δffmsin⁡ωmt=ωct+βsin⁡ωmt\theta_i(t) = 2\pi\int_0^t f_i(\tau)\,d\tau = \omega_ct + \frac{\Delta f}{f_m}\sin\omega_mt = \omega_ct + \beta\sin\omega_mt

with modulation index β=Δf/fm\beta = \Delta f/f_m. So

s(t)=Accos⁡(ωct+βsin⁡ωmt)s(t) = A_c\cos(\omega_ct + \beta\sin\omega_mt)

Complex envelope and Fourier series

s(t)=Re[Ac ejβsin⁡ωmt ejωct]s(t) = \text{Re}\left[A_c\,e^{j\beta\sin\omega_mt}\,e^{j\omega_ct}\right]

The term s~(t)=Acejβsin⁡ωmt\tilde s(t) = A_ce^{j\beta\sin\omega_mt} is periodic with period Tm=1/fmT_m = 1/f_m, so it has a Fourier series:

s~(t)=∑n=−∞∞cnejnωmt\tilde s(t) = \sum_{n=-\infty}^{\infty} c_n e^{jn\omega_mt} cn=1Tm∫−Tm/2Tm/2Acejβsin⁡ωmte−jnωmtdtc_n = \frac{1}{T_m}\int_{-T_m/2}^{T_m/2} A_c e^{j\beta\sin\omega_mt}e^{-jn\omega_mt}dt

Put x=ωmtx = \omega_mt (dt=dx/ωmdt = dx/\omega_m, limits −π-\pi to π\pi):

cn=Ac2π∫−ππej(βsin⁡x−nx)dx=AcJn(β)c_n = \frac{A_c}{2\pi}\int_{-\pi}^{\pi} e^{j(\beta\sin x - nx)}dx = A_cJ_n(\beta)

where Jn(β)J_n(\beta) is the Bessel function of the first kind of order n:

Jn(β)=12π∫−ππej(βsin⁡x−nx)dxJ_n(\beta) = \frac{1}{2\pi}\int_{-\pi}^{\pi}e^{j(\beta\sin x - nx)}dx

Final expression

s~(t)=Ac∑n=−∞∞Jn(β)ejnωmt\tilde s(t) = A_c\sum_{n=-\infty}^{\infty}J_n(\beta)e^{jn\omega_mt} s(t)=Re[Ac∑nJn(β)ej(ωc+nωm)t]=Ac∑n=−∞∞Jn(β)cos⁡[(ωc+nωm)t]s(t) = \text{Re}\left[A_c\sum_n J_n(\beta)e^{j(\omega_c + n\omega_m)t}\right] = A_c\sum_{n=-\infty}^{\infty}J_n(\beta)\cos[(\omega_c + n\omega_m)t]

Expanded, using J−n(β)=(−1)nJn(β)J_{-n}(\beta) = (-1)^nJ_n(\beta):

s(t)=AcJ0(β)cos⁡ωct+AcJ1(β)[cos⁡(ωc+ωm)t−cos⁡(ωc−ωm)t]+AcJ2(β)[cos⁡(ωc+2ωm)t+cos⁡(ωc−2ωm)t]+…\begin{aligned} s(t) &= A_cJ_0(\beta)\cos\omega_ct \\ &\quad + A_cJ_1(\beta)[\cos(\omega_c+\omega_m)t - \cos(\omega_c-\omega_m)t] \\ &\quad + A_cJ_2(\beta)[\cos(\omega_c+2\omega_m)t + \cos(\omega_c-2\omega_m)t] + \dots \end{aligned}

Conclusions

  1. The spectrum has a carrier at fcf_c (amplitude AcJ0(β)A_cJ_0(\beta)) and infinite sidebands at fc±nfmf_c \pm nf_m with amplitudes Ac∣Jn(β)∣A_c|J_n(\beta)|.
  2. Odd-order lower sidebands have reversed sign.
  3. The carrier amplitude depends on β\beta and becomes zero when J0(β)=0J_0(\beta) = 0 (β = 2.405, 5.52, ...).
  4. Since ∑Jn2(β)=1\sum J_n^2(\beta) = 1, total power is constant: P=Ac2/2P = A_c^2/2.
  5. Only about β+1\beta + 1 sidebands on each side are significant, giving Carson's rule BT≈2(β+1)fm=2(Δf+fm)B_T \approx 2(\beta+1)f_m = 2(\Delta f + f_m).

✓ Answer checked by Claude Opus 5.5 (high effort)

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