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Importance of source encoder; Huffman algorithm

Short answer

Source encoder reduces bit rate by assigning shorter codes to frequent symbols, matching average length to entropy. Huffman algorithm: repeatedly merge two lowest-probability symbols, assign bits 0/1, and read codes backwards from final root to leaves.

Elaborate importance of source encoder? Write algorithm for Huffman's coding.

Importance of source encoder

The source encoder converts the source symbols into binary code words with the minimum average number of bits by removing redundancy.

  • It reduces the average code length toward the entropy (Lˉ→H\bar L \to H), so the bit rate, bandwidth and power needed are reduced.
  • It gives short code words to frequent symbols and long ones to rare symbols (variable-length coding).
  • It produces uniquely decodable (prefix) codes, so the receiver can decode without separators.
  • It saves storage space and makes room for channel coding redundancy.

Huffman coding algorithm

  1. Sort: list all source symbols in decreasing order of probability.
  2. Merge: combine the two symbols of lowest probability into one new symbol whose probability is the sum of the two.
  3. Reorder: insert the new probability into the list in its proper place (as high as possible among equal values); the list now has one fewer entry.
  4. Repeat steps 2–3 until only one entry (probability 1) is left.
  5. Assign bits: at each merge, give 0 to one branch (upper) and 1 to the other (lower).
  6. Read codes: trace each symbol's path from the final stage back to its original position; the bits along the path form its code word.
  7. Evaluate: Lˉ=∑pili\bar L = \sum p_i l_i, H=∑pilog⁡2(1/pi)H = \sum p_i\log_2(1/p_i), efficiency η=H/Lˉ\eta = H/\bar L.

Short example: P={0.5,0.25,0.125,0.125}P = \{0.5, 0.25, 0.125, 0.125\} → merge 0.125 + 0.125 = 0.25, then 0.25 + 0.25 = 0.5, then 0.5 + 0.5 = 1. Codes: 0, 10, 110, 111; Lˉ=1.75=H\bar L = 1.75 = H, η=100%\eta = 100\%.

✓ Answer checked by Claude Opus 5.5 (high effort)

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