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Synchronous detection of DSB-SC; phase and frequency error

Short answer

Synchronous demodulator multiplies DSB-SC with local oscillator and low-pass filters. Phase error attenuates output by cosφ, zero when φ=90°. Frequency error multiplies output by cos(Δωt), causing periodic fading and distortion. Exact carrier synchronization is required.

How can synchronous demodulator be used to detect DSB-SC wave? Explain mathematically, the effects of phase error and frequency error in local oscillator while demodulating DSB-SC.

Synchronous (coherent) detection of DSB-SC

A DSB-SC wave s(t)=Acm(t)cos⁡ωcts(t) = A_c m(t)\cos\omega_ct has no carrier, so its envelope is ∣m(t)∣|m(t)|, not m(t)m(t). It is detected by multiplying with a locally generated carrier of the same frequency and phase, then low-pass filtering.

 s(t) --->( X )--->[ LPF, BW = W ]---> v_o(t)
            ^
            |
   [ Local oscillator cos(wc t) ]

With an ideal local carrier cos⁡ωct\cos\omega_ct:

v(t)=Acm(t)cos⁡2ωct=Ac2m(t)+Ac2m(t)cos⁡2ωctv(t) = A_cm(t)\cos^2\omega_ct = \frac{A_c}{2}m(t) + \frac{A_c}{2}m(t)\cos 2\omega_ct

The LPF removes the 2ωc2\omega_c term, so vo(t)=Ac2m(t)v_o(t) = \frac{A_c}{2}m(t), an exact copy of the message.

Effect of phase error

Let the local carrier be cos⁡(ωct+ϕ)\cos(\omega_ct + \phi):

v(t)=Acm(t)cos⁡ωctcos⁡(ωct+ϕ)=Ac2m(t)[cos⁡ϕ+cos⁡(2ωct+ϕ)]vo(t)=Ac2m(t)cos⁡ϕ\begin{aligned} v(t) &= A_cm(t)\cos\omega_ct\cos(\omega_ct+\phi) \\ &= \frac{A_c}{2}m(t)[\cos\phi + \cos(2\omega_ct + \phi)] \\ v_o(t) &= \frac{A_c}{2}m(t)\cos\phi \end{aligned}
  • The output is the message scaled by cos⁡ϕ\cos\phi: an attenuation, not a distortion, if ϕ\phi is constant.
  • At ϕ=±90∘\phi = \pm 90^\circ the output is zero (quadrature null effect).
  • If ϕ\phi drifts randomly with time, the gain varies and the output fades.

Effect of frequency error

Let the local carrier be cos⁡(ωc+Δω)t\cos(\omega_c + \Delta\omega)t:

v(t)=Ac2m(t)[cos⁡Δωt+cos⁡(2ωc+Δω)t]vo(t)=Ac2m(t)cos⁡(Δω t)\begin{aligned} v(t) &= \frac{A_c}{2}m(t)[\cos\Delta\omega t + \cos(2\omega_c + \Delta\omega)t] \\ v_o(t) &= \frac{A_c}{2}m(t)\cos(\Delta\omega\,t) \end{aligned}
  • The message is multiplied by a slowly varying cosine at Δf\Delta f. The output rises and falls periodically and passes through zero twice every 1/Δf1/\Delta f seconds: a "beating" effect.
  • In spectrum terms, m(t)m(t) is shifted to ±Δf\pm\Delta f, which badly distorts speech and music.

So DSB-SC needs exact carrier synchronization in both frequency and phase, using a pilot carrier or a Costas loop / squaring loop.

✓ Answer checked by Claude Opus 5.5 (high effort)

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