- 2079 Asoj · 6 marks
Closed loop better than open loop (cruise)
Short answer
Closed-loop cruise measures speed and computes u=Kp·(r-v), reducing slope error from d/b (open-loop) to d/(b+Kp). Adding integral term u=Kp·e+Ki∫e dt forces steady-state error to zero regardless of disturbance or parameter changes. Trade-off: requires speed sensor and gain tuning to avoid oscillation.
How is a closed loop control system better than an open loop controller? Explain with the example of a cruise control system.
A closed-loop controller measures the actual output and corrects the control action, so it can compensate for disturbances and model errors that an open-loop controller never sees.
Cruise control example
Plant: m·dv/dt = -b·v + u + d (u = engine force, d = slope force, v = speed, r = set speed).
Open loop:
r --> [K=b] --u--> (+)--> [Car] --> v
^ d
Closed loop:
r -->(+)--e--> [Kp] --u--> (+)--> [Car] --+--> v
^ - ^ d |
+------ [speed sensor] <------------+
- Open loop: u = b·r. In steady state v = r + d/b. On an uphill (d negative) the car slows down and the controller does nothing. If the mass or drag changes, v also drifts.
- Closed loop (P): u = Kp·(r - v). Steady state: v = (Kp·r + d)/(b + Kp). The error from the slope becomes d/(b + Kp), which is smaller than d/b, and shrinks as Kp grows.
- With an integral term: u = Kp·e + Ki·∫e dt. In steady state e must be zero, so v = r regardless of slope.
Why closed loop is better
| Point | Open loop | Closed loop |
|---|---|---|
| Road disturbance | Speed error d/b | Reduced to d/(b+Kp), or zero with I |
| Parameter change | Speed drifts | Compensated |
| Needs accurate model | Yes | Less so |
| Needs speed sensor | No | Yes |
Cost: a sensor, and the gain must be limited to avoid overshoot and oscillation.
✓ Answer checked by Claude Opus 5.5 (high effort)
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