Skip to main content

Emergency supply and Ah vs Wh efficiency

Short answer

Emergency supply independently powers essential loads when normal supply fails, using batteries, UPS, DG with AMF, or a second feeder. Ah efficiency is Ah out divided by Ah in; Wh efficiency is Wh out divided by Wh in, and is lower because charge voltage exceeds discharge voltage; example gives 80% and 72.13%.

What is emergency supply system for industrial plant? Differentiate between Ah efficiency and Wh efficiency of battery.

Emergency supply system for an industrial plant

An emergency supply system is an independent, automatically started power source that supplies the essential loads of a plant when the normal supply fails, to protect life, equipment and critical processes.

Essential loads: escape and exit lighting, fire alarm, fire pumps, lifts, control and protection supplies, process loads needing safe shutdown (cooling, stirring, lubrication), communication and security.

Sources:

  1. Battery systems – self-contained or central battery; supply is instant.
  2. UPS – no-break supply for computers, PLCs and instruments.
  3. Diesel generator with AMF panel – starts automatically in about 10–15 s; feeds large loads for long periods.
  4. Second utility feeder with automatic transfer switch (ATS).
 Utility ─►[ATS]─► Essential bus ─► fire pump, lights
             ▲
 DG set ─────┘
 Battery/UPS ─────► PLC, alarm, control (no break)

Essential loads are kept on a separate bus, batteries are on float/trickle charge, and the system is tested regularly.

Ah efficiency vs Wh efficiency

η_Ah = Ah delivered on discharge / Ah supplied on charge
η_Wh = Wh delivered on discharge / Wh supplied on charge
     = η_Ah × (V_avg discharge / V_avg charge)
PointAh efficiencyWh efficiency
Based onQuantity of charge onlyEnergy (charge × voltage)
Considers voltageNoYes
Losses includedGassing, side reactionsAlso I²R and polarisation losses
Value (lead-acid)80–90%70–80%
RelationAlways higherLower, since V_charge > V_discharge
UseDeciding charging time/Ah neededEnergy cost and economics

Example: discharge 4 A × 12 h at 2.2 V, charge 3 A × 20 h at 2.44 V → η_Ah = 48/60 = 80%, η_Wh = 105.6/146.4 = 72.13%.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Industrial Power Distribution and Illumination chapter 9 questions →