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Types of outlets and flexibility

Short answer

Outlets are non-modular, semi-modular, or modular. Proportionality means discharge changes in same proportion as distributary flow; flexibility F = (m/n)(D/H). F=1 is proportional, >1 hyper-proportional, <1 sub-proportional.

Describe briefly the different types of canal outlets. Define proportionality and flexibility of such outlets.

Types of canal outlets (4 marks)

An outlet is a structure that feeds the water course from a distributary. By dependency of its discharge on water levels, it is:

TypeDischarge depends onExamples
Non-modularWater level of distributary and water courseOpen sluice, drowned pipe outlet
Semi-modularDistributary level only (water course must not drown it)Pipe outlet (free), Kennedy gauge outlet, Crump's open flume, adjustable orifice semi-module
Modular (rigid)Neither level (constant discharge)Gibb's rigid module, Khanna's rigid module, Foote module

Proportionality (2 marks)

An outlet is proportional if its discharge changes in the same proportion as the discharge in the distributary, so every outlet takes its fair share of any supply. This needs the flexibility to be one.

Flexibility (2 marks)

Flexibility FF is the ratio of the rate of change of outlet discharge qq to the rate of change of distributary discharge QQ:

F=dq/qdQ/QF = \frac{dq/q}{dQ/Q}

With q=CHmq = CH^{m} for the outlet (head HH) and Q=KDnQ = KD^{n} for the distributary (depth DD), and dH=dDdH = dD, this gives F=mn⋅DHF = \dfrac{m}{n}\cdot\dfrac{D}{H}.

  • F=1F = 1: proportional outlet (shares any change in supply in the same ratio).
  • F>1F > 1: hyper-proportional (takes more than its share when supply rises).
  • F<1F < 1: sub-proportional (takes less than its share when supply rises).

Example: for a wide distributary n≈5/3n \approx 5/3. A free pipe outlet (m=1/2m = 1/2) at bed level (H≈DH \approx D) has F≈0.3F \approx 0.3 (sub-proportional); an open flume (m=3/2m = 3/2) is proportional when its crest is set 0.9D0.9D below the water surface; a rigid module has F=0F = 0.

✓ Answer checked by Claude Opus 5.5 (high effort)

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