- Asked 2/13
- 2072 Magh · 10 marks
Disk scheduling with 5000 cylinders
Short answer
For head at 143 moving upward, FCFS gives 7141 cylinders, SCAN to 4999 then reverse gives 9799, LOOK to 1774 then reverse gives 3349, C-SCAN with return jump counted gives 9985, SSTF gives 1805 cylinders.
Suppose that a disk drive has 5000 cylinders, numbered 0 to 4999. The drive is currently serving a request at cylinder 143, and the previous request was at cylinder 125. The queue of pending requests, in FIFO order is: 56, 1470, 913, 1774, 948, 1509, 1022, 1750, 130 Starting from the current head position, what is the total distance (in cylinder) that the disk arm moves to satisfy all the pending requests, for each of the following algorithms: FCFS, SCAN, LOOK, CSCAN, SSTF
Disk: 5000 cylinders (0 to 4999), head at 143, previous request 125, so the head is moving upward. Queue (FIFO): 56, 1470, 913, 1774, 948, 1509, 1022, 1750, 130.
FCFS
FCFS: service order (head at 143): 56, 1470, 913, 1774, 948, 1509, 1022, 1750, 130
143 -> 56 = 87
56 -> 1470 = 1414
1470 -> 913 = 557
913 -> 1774 = 861
1774 -> 948 = 826
948 -> 1509 = 561
1509 -> 1022 = 487
1022 -> 1750 = 728
1750 -> 130 = 1620
Total = 87 + 1414 + 557 + 861 + 826 + 561 + 487 + 728 + 1620 = 7141
SCAN (up to 4999, then reverse)
SCAN: service order (head at 143): 913, 948, 1022, 1470, 1509, 1750, 1774, 130, 56
143 -> 913 = 770
913 -> 948 = 35
948 -> 1022 = 74
1022 -> 1470 = 448
1470 -> 1509 = 39
1509 -> 1750 = 241
1750 -> 1774 = 24
1774 -> 4999 = 3225
4999 -> 130 = 4869
130 -> 56 = 74
Total = 770 + 35 + 74 + 448 + 39 + 241 + 24 + 3225 + 4869 + 74 = 9799
LOOK (up to 1774, then reverse)
LOOK: service order (head at 143): 913, 948, 1022, 1470, 1509, 1750, 1774, 130, 56
143 -> 913 = 770
913 -> 948 = 35
948 -> 1022 = 74
1022 -> 1470 = 448
1470 -> 1509 = 39
1509 -> 1750 = 241
1750 -> 1774 = 24
1774 -> 130 = 1644
130 -> 56 = 74
Total = 770 + 35 + 74 + 448 + 39 + 241 + 24 + 1644 + 74 = 3349
C-SCAN (up to 4999, jump to 0, continue upward)
C-SCAN: service order (head at 143): 913, 948, 1022, 1470, 1509, 1750, 1774, 56, 130
143 -> 913 = 770
913 -> 948 = 35
948 -> 1022 = 74
1022 -> 1470 = 448
1470 -> 1509 = 39
1509 -> 1750 = 241
1750 -> 1774 = 24
1774 -> 4999 = 3225
4999 -> 0 = 4999 (return jump)
0 -> 56 = 56
56 -> 130 = 74
Total = 770 + 35 + 74 + 448 + 39 + 241 + 24 + 3225 + 4999 + 56 + 74 = 9985
SSTF
SSTF: service order (head at 143): 130, 56, 913, 948, 1022, 1470, 1509, 1750, 1774
143 -> 130 = 13
130 -> 56 = 74
56 -> 913 = 857
913 -> 948 = 35
948 -> 1022 = 74
1022 -> 1470 = 448
1470 -> 1509 = 39
1509 -> 1750 = 241
1750 -> 1774 = 24
Total = 13 + 74 + 857 + 35 + 74 + 448 + 39 + 241 + 24 = 1805
Summary
| Algorithm | Total head movement (cylinders) |
|---|---|
| FCFS | 7141 |
| SCAN | 9799 |
| LOOK | 3349 |
| C-SCAN | 9985 (4986 if the return sweep is not counted) |
| SSTF | 1805 |
Answer: FCFS 7141, SCAN 9799, LOOK 3349, C-SCAN 9985, SSTF 1805 cylinders.
✓ Answer checked by Claude Opus 5.5 (high effort)
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