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Aperture antennas and rectangular horn radiation

Short answer

Aperture antennas radiate from fields across an opening (Huygens sources) unlike wire antennas using currents, giving high gain at microwaves. A rectangular horn flares a TE10 waveguide; the aperture field is cosine across H-plane and uniform across E-plane. Optimum horn: phase error <0.25λ E-plane, <0.4λ H-plane; HPBWE≈56λ/a_E, HPBWH≈67λ/a_H, directivity≈7.5 a_E a_H/λ².

How are aperture type of antennas different from the conventional antennas? Explain the theory of radiation from a rectangular horn.

Aperture antennas vs conventional (wire) antennas

PointWire (conventional) antennaAperture antenna
Radiating sourceCurrents on thin conductorsFields across an opening
AnalysisCurrent distribution integrated along wireAperture field (Huygens sources), Fourier transform
SizeComparable to λ (λ/2, λ/4)Many wavelengths across
FrequencyLF to UHFMicrowave (above ~1 GHz)
GainLow to moderateHigh (gain ∝ aperture area)
ExamplesDipole, monopole, loopHorn, slot, dish, lens

Theory of radiation from a rectangular horn

A rectangular horn is a rectangular waveguide (dominant TE₁₀ mode) flared into a larger aperture of size a_H × a_E. The flare matches the guide impedance to free space (377 Ω) and enlarges the aperture to give a directive beam.

          side view (E or H plane)
            .-‾‾‾‾‾|
   ____  .-'   δ   |   L = axial length
  |____|<-----L--->|   a = aperture width
         '-._______|   δ = path difference
  1. Aperture field: the TE₁₀ field is carried to the aperture. Across the H-plane width the amplitude is cosine shaped, cos(πx/a_H); across the E-plane it is uniform.
  2. Phase error: waves from the throat reach the aperture edge by a longer path than along the axis. The extra path is
δ = √(L² + (a/2)²) − L ≈ a²/(8L)

A large δ gives a non-uniform phase, broadening the beam and lowering gain. 3. Radiation: each element of the aperture acts as a Huygens source; integrating them (a Fourier transform of the aperture field) gives the far field. Uniform E-plane distribution gives a sin(u)/u pattern (narrow beam, higher side lobes ≈ −13 dB); cosine H-plane distribution gives a wider beam with lower side lobes (≈ −23 dB). 4. Optimum horn: δ ≈ 0.25λ in the E-plane and ≈ 0.4λ in the H-plane gives maximum gain for a given length, L = a²/(8δ). 5. Optimum-horn results:

HPBW (E-plane) ≈ 56 λ / a_E   degrees
HPBW (H-plane) ≈ 67 λ / a_H   degrees
Directivity    D ≈ 7.5 a_E a_H / λ²   (η ≈ 0.6)

So a longer horn with a bigger mouth gives more gain, as long as the phase error is kept within the optimum limit.

✓ Answer checked by Claude Opus 5.5 (high effort)

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