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Importance of arrays; end fire vs broadside

Short answer

Antenna arrays provide high directivity, beam steering, and power sharing. A broadside array has all elements in phase (δ=0) radiating perpendicular to the axis. An end-fire array has progressive phase δ = -βd, radiating along the axis. End-fire gives higher directivity (~4Nd/λ) than broadside (~2Nd/λ).

What is the importance of antenna array? Describe the principle of End fire and Broadside array, and differentiate between them.

An antenna array is a group of similar antennas arranged in a regular geometry and fed with controlled amplitudes and phases so that their fields add in the desired directions.

Importance of antenna array

  • Gives high directivity and gain that one small element cannot give.
  • Narrow, steerable beam: the beam direction can be changed electronically by changing the phase (phased arrays, radar).
  • The pattern can be shaped: low side lobes, nulls towards interference.
  • Higher total power handling, since the power is shared by many elements.
  • Better reliability: failure of one element does not stop operation.

For a uniform linear array of N elements, spacing d, progressive phase δ:

ψ = βd cosθ + δ
AF = sin(Nψ/2) / [N sin(ψ/2)]
Maximum when ψ = 0

Broadside array

  • All elements are fed in phase (δ = 0).
  • ψ = 0 at θ = 90°, so maximum radiation is perpendicular to the array axis.
  • The pattern is a disk-like beam around the axis (narrow in the plane containing the axis).

End-fire array

  • Progressive phase δ = −βd, i.e. each element lags the previous one by the phase delay over spacing d.
  • ψ = βd(cosθ − 1) = 0 at θ = 0°, so maximum radiation is along the array axis.
 Broadside                End-fire
      ^ ^ ^ ^                 
      | | | |             o o o o o  ====>
   o--o--o--o--o          max along axis
   max perpendicular

Difference

PointBroadsideEnd-fire
Phase shift δ0 (in phase)−βd (progressive)
Max direction⊥ to array axis (θ = 90°)Along axis (θ = 0°)
PatternFan/disk shapedCigar/pencil along axis
BWFN≈ 2λ/(Nd)≈ 2√(2λ/(Nd))
Directivity≈ 2Nd/λ≈ 4Nd/λ
Example N = 10, d = λ/4BWFN ≈ 46°, D ≈ 5BWFN ≈ 103°, D ≈ 10
Typical useBroadcast, base stationsYagi-Uda, log-periodic, point-to-point

The end-fire spacing is kept below λ/2: with d = λ/2 and δ = −βd, a second equal main lobe appears at θ = 180°, and the directivity drops to about that of a broadside array.

✓ Answer checked by Claude Opus 5.5 (high effort)

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