- Asked 2/20
- 2072 Magh · 6 marks
Current distribution of λ, 3λ/2 and 2λ dipoles
Sketch the current distribution and radiation pattern of center-fed vertical dipole for following lengths: i) λ ii) 3λ/2 iii) 2λ
For a centre-fed thin dipole of length L, the current is a standing wave that is zero at the open ends:
I(z) = I0 sin[k(L/2 − |z|)]
E(θ) ∝ [cos((kL/2)cosθ) − cos(kL/2)] / sinθ
(θ measured from the dipole axis; patterns are omnidirectional in the horizontal plane.)
i) L = λ
Current E-plane pattern
/\ z
/ \ upper half-loop |
\ / feed: I ≈ 0 .--. | .--.
\/ lower half-loop( )|( )
(both in phase) '--' | '--'
- Two half-wave loops, in phase, with current minimum (zero) at the feed point, so input impedance is very high.
- E(θ) = [cos(π cosθ) + 1]/sinθ; single broadside lobe each side, narrower than λ/2.
- HPBW ≈ 47.8°, D ≈ 2.41 (3.82 dBi).
ii) L = 3λ/2
Current: + | − | + (3 half-loops,
centre loop opposite phase)
Pattern: \ | /
( ) | ( ) major lobes
( )---+---( ) at 42.6°, 137.4°
( ) | ( ) minor lobe at 90°
/ | \
- Three half-loops; centre loop opposite to the outer ones; current maximum at the feed (R_in ≈ 105 Ω).
- 6 lobes: major lobes at θ ≈ 42.6° and 137.4°, smaller broadside lobe at 90° (≈ −2.9 dB), nulls at ≈ 70.5° and 109.5°.
- D ≈ 2.23 (3.48 dBi).
iii) L = 2λ
Current: + − | − + → 2 loops each arm;
adjacent loops opposite phase,
zero current at feed
Pattern: \ | /
( ) | ( ) 4 lobes at
---------+--------- 57.4°, 122.6°
( ) | ( ) null at 90°
/ | \
- Four half-loops; the two loops on each arm are in opposite phase; current zero at the feed.
- E(θ) = [cos(2π cosθ) − 1]/sinθ → null broadside (θ = 90°) and along the axis.
- 4 lobes (cloverleaf), maxima at θ ≈ 57.4° and 122.6°; D ≈ 2.53 (4.03 dBi).
As L increases beyond λ, phase reversals in the current split the pattern into more lobes.
✓ Answer checked by Claude Opus 5.5 (high effort)
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