- 2072 Asoj · 3 marks
Short note: NA for meridional rays
Short answer
For meridional rays, which pass through the fibre axis, NA = n0 sin θa = sqrt(n1² − n2²) ≈ n1√(2Δ). Only rays inside the acceptance cone of half-angle θa are guided; NA depends only on core and cladding indices. Example: n1=1.48, n2=1.46 gives NA=0.2425, θa=14.03°.
Write a short note on NA for meridional rays in optical fiber.
Numerical aperture (NA) of a fibre measures its light-gathering ability. For meridional rays (rays that pass through the fibre axis and stay in one plane), it is the sine of the maximum acceptance angle multiplied by the index of the outside medium.
n0 cladding n2
\ ________________________
th0\/ phi /\ /\
----*-----/--\----/--\---- axis core n1
________________________
A ray entering at angle is refracted to (Snell's law ) and meets the core–cladding boundary at . It is guided only if where . At the limit:
where is the relative index difference.
Key points
- NA depends only on and , not on core size.
- Rays inside the cone of half-angle are guided; others leak into the cladding.
- Typical values: 0.1–0.15 (single mode), 0.2–0.3 (multimode).
- Example: , gives NA and in air.
- Skew rays (not passing through the axis) can be accepted at slightly larger angles, so the meridional NA is the standard, conservative value.
✓ Answer checked by Claude Opus 5.5 (high effort)
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