- 2080 Asoj · 2+6 marks
Pattern multiplication, quadrature-phase sources
Short answer
Pattern multiplication: array field pattern equals element pattern times array factor of isotropic sources. For two isotropic sources with equal amplitude, quadrature phase (α=-π/2), d=λ/4: array factor E_n = cos[(π/4)(cosθ-1)]. Maximum at θ=0° (toward lagging source), null at θ=180°, forming a cardioid unidirectional end-fire pattern.
Define pattern multiplication. Derive the expression for far field pattern of an array of two isotropic point sources having equal amplitude and quadrature phase with d = λ/4.
Pattern multiplication
Pattern multiplication states that the field pattern of an array of identical, similarly oriented non-isotropic elements is the product of the pattern of one element and the pattern of the array made of isotropic point sources (array factor). Total phase = element phase + array phase.
E(θ) = E_element(θ) × E_array(θ)
Two isotropic sources, equal amplitude, quadrature phase, d = λ/4
Let source 1 and source 2 lie on the x-axis, spacing d, with the current of source 2 lagging source 1 by 90° (α = −π/2). θ is measured from the axis, midpoint O as reference.
P (far field)
/
/ θ
1 ●-----O-----● 2 -> axis (θ = 0°)
<- d/2 -><- d/2->
path difference = d cosθ
Total phase difference at P:
ψ = βd cosθ + α
βd = (2π/λ)(λ/4) = π/2 , α = -π/2
ψ = (π/2) cosθ - π/2 = (π/2)(cosθ - 1)
Adding the two fields:
E = E₀ e^(-jψ/2) + E₀ e^(jψ/2) = 2E₀ cos(ψ/2)
E = 2E₀ cos[(π/4)(cosθ - 1)]
Normalised: E_n = cos[(π/4)(cosθ - 1)]
Pattern values
| θ | cosθ − 1 | E_n |
|---|---|---|
| 0° | 0 | 1.000 |
| 60° | −0.5 | 0.924 |
| 90° | −1 | 0.707 |
| 120° | −1.5 | 0.383 |
| 180° | −2 | 0 |
Maximum at θ = 0° (towards the lagging source, along the axis); null at θ = 180°. The pattern is a cardioid (unidirectional end fire).
90° (0.707)
.--''--.
.' '.
180° 0 1 2 > 0° (max = 1)
'. .'
'--..--'
270°
Physical reason: towards θ = 0°, the wave from source 1 travels λ/4 (90°) to reach source 2, which exactly cancels source 2's 90° lag, so the fields add. Towards θ = 180°, the travel delay and current lag add to 180°, so the fields cancel. If source 2 leads instead (α = +π/2), the cardioid points to θ = 180°.
✓ Answer checked by Claude Opus 5.5 (high effort)
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