- 2080 Asoj · 2+5 marks
Retarded time and retarded potentials
Short answer
Retarded time is t' = t − R/v, the earlier time at which the source state must be taken. The retarded potentials are V = (1/4πε)∫ρ(t−R/v)/R dv and A = (μ/4π)∫J(t−R/v)/R dv; they satisfy the wave equation and give E and B via E = −∇V − ∂A/∂t, B = ∇×A.
What is the retarded time? Explain the retarded vector and scalar potential with mathematical expression.
Retarded time is the earlier time at which a signal must leave the source to reach the observation point at the present time t:
t' = t − R/v
where R = distance from source to point and v = speed of propagation (c in free space). The field at P now depends on what the source was doing at t'.
Retarded potentials
For static sources:
V = (1/4πε) ∫ ρ / R dv, A = (μ/4π) ∫ J / R dv
For time-varying sources, ρ and J are taken at the retarded time:
V(r, t) = (1/4πε) ∫ [ρ(r', t − R/v)] / R dv'
A(r, t) = (μ/4π) ∫ [J(r', t − R/v)] / R dv'
These are the retarded scalar potential and retarded vector potential. They satisfy the wave equations:
∇²V − με ∂²V/∂t² = −ρ/ε
∇²A − με ∂²A/∂t² = −μJ
with the Lorenz gauge ∇·A = −με ∂V/∂t.
Phasor (time-harmonic) form, with e^(jωt) and k = ω/v = 2π/λ:
V = (1/4πε) ∫ ρ e^(−jkR) / R dv'
A = (μ/4π) ∫ J e^(−jkR) / R dv'
The factor e^(−jkR) is the phase delay of retardation.
For a line current I (wire antenna): A = (μ/4π) ∫ I e^(−jkR)/R dl.
Fields are then found from
B = ∇ × A
E = −∇V − ∂A/∂t (= −∇V − jωA)
Importance: retarded potentials explain why time-varying currents produce fields that travel outward with finite speed and a 1/r part – the radiation field. All antenna fields (dipole, loop, arrays) are derived from them.
✓ Answer checked by Claude Opus 5.5 (high effort)
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