- 2078 Chaitra · 8 marks
First and second stage BOD
Short answer
First-stage BOD (carbonaceous) involves oxidation of organic carbon, largely complete in20 days. Second-stage BOD (nitrogenous) starts after ~8-10 days with ammonia oxidation. Assuming standard rate constant k=0.1/day (base10) at20°C, ultimate BOD =400/(1-10^(-0.5)) =585.0 mg/L.
Discuss first-stage and second stage BOD with a suitable figure. Calculate ultimate BOD if 5 day BOD of sewage sample at 20°C is 400 mg/l.
First-stage BOD (carbonaceous)
In the first stage, bacteria oxidise the carbonaceous organic matter into CO₂ and water. It is practically complete in about 20 days at 20°C (with day⁻¹, about 68% in 5 days and 99% in 20 days). The first stage is called carbonaceous BOD (CBOD).
Second-stage BOD (nitrogenous)
After about 8-10 days, nitrifying bacteria (Nitrosomonas, Nitrobacter) oxidise ammonia to nitrite and then to nitrate, using more oxygen:
This is the nitrogenous BOD (NBOD). Because the nitrifiers grow slowly, it does not appear in the standard 5 day test at 20°C.
BOD exerted
| ______ second stage
| _____/ (nitrification)
| _____/___
| __/ first stage ends (L)
| /
| /
+----+----+----+----+----> days
0 5 10 15 20
The first-stage curve is . The second-stage curve starts at about the 8th-10th day and rises above it.
Ultimate BOD calculation
The rate constant is not given, so the standard value day⁻¹ (base 10) is assumed.
Answer: Ultimate first-stage BOD = 585.0 mg/L (with /day base 10; with the equivalent /day base the result is nearly the same, 585.3 mg/L).
✓ Answer checked by Claude Opus 5.5 (high effort)
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