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Enthalpy formulation and heat transfer equation

Short answer

The enthalpy equation is ρ Dh/Dt = Dp/Dt + ∇·(k∇T) + Φ + S_h, representing enthalpy change, pressure work, conduction, viscous dissipation, and heat source. For incompressible constant-property flow with negligible dissipation and pressure work, it simplifies to ρcₚ DT/Dt = k∇²T + q̇, a convection–diffusion temperature equation.

Write the energy equation in terms of enthalpy for a viscous flow and explain its terms. Show how it simplifies to the heat transfer (temperature) equation for an incompressible fluid with constant properties.

The energy equation comes from the first law of thermodynamics applied to a fluid element: the rate of change of energy equals the heat added plus the work done on the element.

Enthalpy form

With specific enthalpy h=e+p/ρh=e+p/\rho, the transport equation is

ρDhDt=DpDt+∇⋅(k∇T)+Φ+Sh\rho\frac{Dh}{Dt}=\frac{Dp}{Dt}+\nabla\cdot(k\nabla T)+\Phi+S_h

that is

ρ(∂h∂t+V⃗⋅∇h)=∂p∂t+V⃗⋅∇p+∇⋅(k∇T)+Φ+Sh\rho\left(\frac{\partial h}{\partial t}+\vec V\cdot\nabla h\right)=\frac{\partial p}{\partial t}+\vec V\cdot\nabla p+\nabla\cdot(k\nabla T)+\Phi+S_h
TermMeaning
ρ Dh/Dt\rho\,Dh/DtRate of change of enthalpy of a moving fluid element
Dp/DtDp/DtWork of pressure changes; important for compressible flow
∇⋅(k∇T)\nabla\cdot(k\nabla T)Heat conduction (Fourier's law)
Φ\PhiViscous dissipation: mechanical work converted to heat
ShS_hVolumetric heat source (reaction, radiation, Joule heating)

For an ideal gas dh=cp dTdh=c_p\,dT. For an incompressible liquid dh=c dT+dp/ρdh=c\,dT+dp/\rho, and the dp/ρdp/\rho part cancels the Dp/DtDp/Dt term. Either way, the equation can be written in terms of temperature.

Simplification

For incompressible flow with constant ρ, cp, k\rho,\ c_p,\ k and negligible viscous dissipation and pressure work (low speed):

ρcp(∂T∂t+u∂T∂x+v∂T∂y+w∂T∂z)=k∇2T+q˙\rho c_p\left(\frac{\partial T}{\partial t}+u\frac{\partial T}{\partial x}+v\frac{\partial T}{\partial y}+w\frac{\partial T}{\partial z}\right)=k\nabla^2T+\dot q

or

∂T∂t+V⃗⋅∇T=α∇2T+q˙ρcp,α=kρcp\frac{\partial T}{\partial t}+\vec V\cdot\nabla T=\alpha\nabla^2T+\frac{\dot q}{\rho c_p},\qquad \alpha=\frac{k}{\rho c_p}

This is the convection-diffusion equation for temperature.

Special cases

  • No flow (V⃗=0\vec V=0): ∂T/∂t=α∇2T\partial T/\partial t=\alpha\nabla^2T, the transient heat conduction equation.
  • Steady, no flow, no source: ∇2T=0\nabla^2T=0, the Laplace equation.
  • Steady 1D conduction with source: k d2T/dx2+q˙=0k\,d^2T/dx^2+\dot q=0.

The ratio of convection to conduction is the Peclet number Pe=ρcpVL/k=Re PrPe=\rho c_pVL/k=Re\,Pr.

✓ Answer checked by Claude Opus 5.5 (high effort)

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