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LTI output for 2δ(n) − δ(n−1) input

Short answer

By linearity and time-invariance, y(n)=2h(n)-h(n-1): y(n)={2,5,1,-4,3,-1} for n=-1 to 4.

A discrete time LTI system has impulse response h(n) = {1, 3, 2, −1, 1} for −1 ≤ n ≤ 3. Determine the system output y(n) if the input x(n) is given by x(n) = 2δ(n) − δ(n−1).

Given: h(n) = {1, 3, 2, −1, 1} for n = −1 … 3, so h(−1) = 1, h(0) = 3, h(1) = 2, h(2) = −1, h(3) = 1.

Input x(n) = 2δ(n) − δ(n − 1).

Because the system is LTI, linearity and time-invariance give

y(n) = 2h(n) − h(n − 1)

(an impulse δ(n − k) produces h(n − k)).

n−101234
2h(n)264−220
−h(n−1)0−1−3−21−1
y(n)251−43−1

Answer: y(n) = {2, 5, 1, −4, 3, −1} for n = −1 … 4.

Check: Σy = 6; (Σx)(Σh) = (2 − 1)(1 + 3 + 2 − 1 + 1) = 6. ✓

✓ Answer checked by Claude Opus 5.5 (high effort)

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