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Gas turbine improvement methods and regeneration

Short answer

Common methods: regeneration, intercooling, reheating, higher turbine inlet temperature, combined cycles. Regeneration preheats compressed air with exhaust, reducing fuel input for the same net work, thus raising thermal efficiency; works best when turbine exhaust is hotter than compressor outlet.

List the common methods used for the performance improvement of the gas turbine power plants. Explain how regeneration increases efficiency of the plant.

Common methods to improve gas turbine performance

  1. Regeneration – exhaust heat preheats compressed air.
  2. Intercooling – multi-stage compression with cooling between stages.
  3. Reheating – multi-stage expansion with reheating between turbines.
  4. Combination of regeneration, intercooling and reheating.
  5. Higher turbine inlet temperature (better materials, blade cooling).
  6. Optimum pressure ratio and higher compressor/turbine efficiencies; low pressure losses.
  7. Combined cycle / cogeneration using exhaust heat.
  8. Water/steam injection and inlet air cooling.

How regeneration increases efficiency

In a simple open cycle the exhaust leaves the turbine at 400–550 °C, often hotter than the air leaving the compressor. A regenerator (counter-flow heat exchanger) passes this hot exhaust over tubes carrying the compressed air.

          +------- REGENERATOR -------+
          | air 2 --> x   y <-- gas 4 |
          +--^--------|---|--------^--+
             |        v   v        |
 Air 1 -->[ C ]    [ CC ]-3->[ T ]-+
            ||       ^ fuel  ||
            ++=====shaft=====++==> Gen
                   exhaust from y
  1. Air leaves the compressor at T2T_2 and is heated in the regenerator to TxT_x by the exhaust gas.
  2. The combustion chamber only has to raise the air from TxT_x to T3T_3, so heat supplied falls from cp(T3−T2)c_p(T_3 - T_2) to cp(T3−Tx)c_p(T_3 - T_x).
  3. Compressor and turbine works are not changed, so net work stays the same while fuel input decreases:
η=Wt−Wccp(T3−Tx)>Wt−Wccp(T3−T2)\eta = \frac{W_t - W_c}{c_p(T_3 - T_x)} > \frac{W_t - W_c}{c_p(T_3 - T_2)}
  1. The exhaust leaves at the lower temperature TyT_y, so less heat is wasted.
  2. Effectiveness ε=Tx−T2T4−T2\varepsilon = \dfrac{T_x - T_2}{T_4 - T_2}, practically 0.6–0.8. With an ideal regenerator (ε=1\varepsilon = 1), η=1−T1T3rp(γ−1)/γ\eta = 1 - \dfrac{T_1}{T_3}r_p^{(\gamma-1)/\gamma}, which increases as pressure ratio decreases.

Limitation: regeneration works only when T4>T2T_4 > T_2 (low/moderate pressure ratios). It adds cost, weight and pressure losses, so it is mainly used in stationary base-load plants.

✓ Answer checked by Claude Opus 5.5 (high effort)

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