- 2080 Baisakh · 3+5 marks
Why insertion loss; double-section shunt-arm LPF
Short answer
The insertion loss method specifies the complete frequency response exactly and enables systematic design from prototype tables. A double-section shunt-arm microstrip LPF uses narrow high-impedance line sections as series inductors and two open-circuited stubs as shunt capacitors.
Explain why insertion loss technique is used to design microwave filters. With proper labeling sketch microwave double-section shunt-arm types microwave LPF using micro strips.
Why the insertion loss technique is used
The insertion loss method designs a filter from a chosen power loss ratio:
PLR = 1 / (1 − |Γ(ω)|²) = 1 + M(ω²)/N(ω²)
Butterworth: PLR = 1 + k²(ω/ωc)^(2N)
Chebyshev : PLR = 1 + k² T_N²(ω/ωc)
It is preferred over the older image-parameter method because:
- the complete response (passband ripple, cut-off sharpness, phase) is specified and achieved exactly,
- the design is systematic: g-value tables, then scaling, then transformation, with no trial and error,
- the order N gives a clear trade-off between performance and size or loss,
- one LP prototype can be turned into HP, BP or BS filters and then into microstrip (Richards, Kuroda, stepped-impedance).
Double-section shunt-arm microwave LPF in microstrip
In a shunt-arm LPF, the shunt capacitors are made as open-circuited stubs (or wide pads) connected across the line, and the series inductors are short high-impedance line sections. A double-section filter has two shunt arms.
Lumped: o--UUU--+--UUU--+--UUU--o
L1 | L2 | L3
C1 C2
| |
o-------+-------+-------o
Microstrip (top view):
stub C1 stub C2
| | | | open end
| | l_s | | (λ/8 at fc)
50 Ω ====+----+-+----+-----+-+----+==== 50 Ω
feed L1 (hi-Z) L2 (hi-Z) L3 feed
-------- ground plane below ------
Labels
- 50 Ω feed lines at input and output.
- L₁, L₂, L₃: narrow high-impedance (about 100–120 Ω) line sections, βl = L·R₀/Z_h (normalised L), acting as series inductors. With Richards and Kuroda design, these are λ/8 unit elements.
- C₁, C₂: open-circuited shunt stubs. From Richards' transformation each is λ/8 long at fc with Z₀ = R₀/g_k. (Wide low-impedance pads can be used instead.)
- Substrate with εr and height h, and a full ground plane underneath.
✓ Answer checked by Claude Opus 5.5 (high effort)
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