- 2079 Chaitra · 3+3 marks
Basic propagation models and far-field distance
Short answer
Basic models include free space (Friis), two-ray ground reflection, log-distance, and log-normal shadowing. Far field distance df = 2D²/λ; with D=1 m, f=900 MHz (λ=0.333 m), gives df = 6 m.
Explain basic propagation models. Compute the far field distance for an antenna with maximum dimension of 1 m and operating frequency of 900 MHz.
Propagation models predict the average received signal strength at a given distance (large-scale models) or its rapid fluctuations over short distances (small-scale/fading models).
Basic propagation models
1. Free space model (Friis) Used when there is a clear, unobstructed LOS path, e.g. satellite and microwave links.
Pr(d) = Pt·Gt·Gr·λ² / [(4π)²d²L]
PL(dB) = 20 log(4πd/λ)
Power falls as 1/d² (20 dB/decade). Valid only in the far field (d ≥ df).
2. Two-ray ground reflection model Considers the direct path plus a ground-reflected path. For large d:
Pr = Pt·Gt·Gr·ht²·hr² / d⁴
Power falls as 1/d⁴ (40 dB/decade). More accurate than free space for long distances over flat ground.
3. Log-distance path loss model
PL(d) = PL(d0) + 10n log(d/d0)
n = 2 free space, 2.7–3.5 urban, 3–5 shadowed urban.
4. Log-normal shadowing Adds a zero-mean Gaussian random variable Xσ (dB) to log-distance loss to account for obstacles: PL(d) = PL(d0) + 10n log(d/d0) + Xσ.
Empirical outdoor models (Okumura, Hata) and indoor models (partition loss, Ericsson) build on these.
Far field distance
The far field (Fraunhofer region) begins at
df = 2D²/λ, with df ≫ D and df ≫ λ
Given D = 1 m, f = 900 MHz:
λ = 3×10⁸ / 900×10⁶ = 0.333 m
df = 2 × 1² / 0.333 = 6 m
Check: 6 m ≫ D (1 m) and 6 m ≫ λ (0.333 m)
Answer: Far field distance df = 6 m.
✓ Answer checked by Claude Opus 5.5 (high effort)
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