- 2070 Magh · 4 marks
Short note: Rayleigh and Ricean fading distribution
Short answer
Rayleigh fading (no LOS) envelope: p(r) = (r/σ²)exp(-r²/2σ²) with deep fades. Ricean fading adds dominant LOS, K = A²/(2σ²); envelope includes I₀(Ar/σ²). Large K gives near-constant envelope; K → -∞ yields Rayleigh.
Write a short note on Rayleigh and Ricean fading distribution.
Rayleigh fading distribution
When there is no line-of-sight path, the received signal is the sum of many scattered waves with random phases. By the central limit theorem its in-phase and quadrature parts are Gaussian, so the envelope r follows the Rayleigh pdf:
p(r) = (r/σ²) exp(−r²/2σ²), 0 ≤ r ≤ ∞
= 0, r < 0
- σ = rms value of the received signal before envelope detection; σ² = time-average power.
- Mean = 1.2533σ, median = 1.177σ, variance = 0.4292σ².
- Models the worst case: deep fades (20–40 dB) occur often. Typical of dense urban areas.
Ricean fading distribution
When a dominant, steady component (LOS path) exists along with random scattered waves, the envelope follows the Ricean pdf:
p(r) = (r/σ²) exp(−(r² + A²)/2σ²) I₀(Ar/σ²),
A ≥ 0, r ≥ 0
- A = peak amplitude of the dominant signal; I₀ = modified Bessel function of first kind, zero order.
- Rician factor K = A²/(2σ²), or K(dB) = 10 log(A²/2σ²).
- As A → 0 (K → −∞ dB) the dominant path fades away and the Ricean distribution becomes Rayleigh. Large K means a nearly constant (Gaussian-like) envelope.
p(r) K = −∞ dB (Rayleigh)
| /\ K = 6 dB
| / \ /\
| / \ / \
|/ \__/ \__
+--------------------> r
✓ Answer checked by Claude Opus 5.5 (high effort)
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