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CST plate: stresses and strains at centroid
Short answer
Use one plane-stress CST element with t=20 mm and nodal coordinates A(0,0), B(4000,0), C(0,3000) mm. Solving with only node B free gives u_B=0.0404 mm and v_B=0.0825 mm. At the centroid, strains are epsilon_x=1.01e-5, epsilon_y=0, gamma_xy=2.06e-5 and stresses are sigma_x=2.333, sigma_y=0.700, tau_xy=1.667 N/mm^2.
A plate of thickness 20 mm is being loaded as shown in the figure. Considering the plane stress condition, determine the stresses and strains at the centroid of the CST element. Take N/mm, . Ignore the weight of the plate.
[Figure: right triangular plate ABC with A at the bottom-left, B at the bottom-right 4 m from A, C directly above A at 3 m; supports at A and C along the left edge; at B a 50 kN upward load and a 70 kN horizontal load (to the right)]
The plate is modelled by one CST element ABC in plane stress ( mm, N/mm, ). Node numbers: A = 1, B = 2, C = 3.
Step 1: Geometry
- Node A (1): mm
- Node B (2): mm
- Node C (3): mm
Area:
mm
mm
Step 2: [B] and [D] matrices (plane stress)
Step 3: Element stiffness matrix
(DOF order: .)
Step 4: Load vector
The 50 kN upward load () and 70 kN horizontal load () act at B (node 2): N, N. Self-weight is ignored (as stated). Coordinates are taken in mm with A at the origin.
Boundary conditions and solution
A and C are on the supported left edge, so . Only are unknown; use rows and columns 3 and 4 of .
Strains and stresses (constant over the element, so equal at the centroid)
Centroid: mm.
Answer: mm, mm. Strains at the centroid: , , . Stresses at the centroid: , , N/mm.
Check: reactions from at A and C are kN and kN; with the loads at B, and .
✓ Answer checked by Claude Opus 5.5 (high effort)
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