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Equilibrium equations for 3D stress

Short answer

Consider an infinitesimal dx dy dz element with body forces X,Y,Z. Force equilibrium gives dsigma_x/dx+dtau_xy/dy+dtau_xz/dz+X=0, dtau_xy/dx+dsigma_y/dy+dtau_yz/dz+Y=0, dtau_xz/dx+dtau_yz/dy+dsigma_z/dz+Z=0; in index form sigma_ij,j+bi=0.

Derive equilibrium equations for the 3D state of stress in a solid.

Consider an infinitesimal element dx dy dzdx\,dy\,dz in equilibrium with body forces per unit volume X,Y,ZX, Y, Z (e.g. self-weight). Stresses vary from face to face, e.g. the normal stress on the face at x+dxx+dx is σx+∂σx∂xdx\sigma_x+\dfrac{\partial\sigma_x}{\partial x}dx.

        y
        ^     sy + dsy
        |   +----------+
  txy   |   |          | sx + dsx
  <-----|   |  dx dy   |---->
   sx   +---+----------+---> x
            sy

Equilibrium of forces in the xx direction

Forces = stress ×\times area. Faces normal to xx have area dy dzdy\,dz, those normal to yy have area dx dzdx\,dz and those normal to zz have area dx dydx\,dy:

(∂σx∂xdx)dy dz+(∂τyx∂ydy)dx dz+(∂τzx∂zdz)dx dy+X dx dy dz=0\Big(\frac{\partial\sigma_x}{\partial x}dx\Big)dy\,dz+\Big(\frac{\partial\tau_{yx}}{\partial y}dy\Big)dx\,dz+\Big(\frac{\partial\tau_{zx}}{\partial z}dz\Big)dx\,dy+X\,dx\,dy\,dz=0

(the terms σx\sigma_x, τyx\tau_{yx}, τzx\tau_{zx} on opposite faces cancel). Dividing by dx dy dzdx\,dy\,dz:

∂σx∂x+∂τxy∂y+∂τxz∂z+X=0\frac{\partial\sigma_x}{\partial x}+\frac{\partial\tau_{xy}}{\partial y}+\frac{\partial\tau_{xz}}{\partial z}+X=0

using τyx=τxy\tau_{yx}=\tau_{xy} and τzx=τxz\tau_{zx}=\tau_{xz} (from moment equilibrium).

Similarly for yy and zz

∂τxy∂x+∂σy∂y+∂τyz∂z+Y=0∂τxz∂x+∂τyz∂y+∂σz∂z+Z=0\begin{aligned} \frac{\partial\tau_{xy}}{\partial x}+\frac{\partial\sigma_y}{\partial y}+\frac{\partial\tau_{yz}}{\partial z}+Y&=0\\ \frac{\partial\tau_{xz}}{\partial x}+\frac{\partial\tau_{yz}}{\partial y}+\frac{\partial\sigma_z}{\partial z}+Z&=0 \end{aligned}

Moment equilibrium about the three axes gives τxy=τyx\tau_{xy}=\tau_{yx}, τyz=τzy\tau_{yz}=\tau_{zy}, τzx=τxz\tau_{zx}=\tau_{xz} (symmetry of the stress tensor).

In compact form:  σij,j+bi=0\ \sigma_{ij,j}+b_i=0.

✓ Answer checked by Claude Opus 5.5 (high effort)

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