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Numerical dispersion, stability; four-point implicit (600 m)
Short answer
Numerical diffusion smears fronts due to even-order truncation error; dispersion causes oscillations from odd-order phase error. Stability requires error not to grow (Courant condition for explicit, implicit unconditionally stable for θ≥0.5). With the four-point implicit method, ∂Q/∂t = 6.94×10⁻⁴ m³/s², ∂Q/∂x = −0.00575 m²/s.
Describe numerical dispersion, diffusion and stability of finite difference schemes. The value of flow rate at four points in the space-time grid are shown in the figure below. Determine the value of first-order derivatives and by using the four-point implicit method. Given: hour, m and .
[Figure: space-time grid with time levels n and n+1 and distance points i and i+1; at (i, n+1) m/s, at (i+1, n+1) m/s, at (i, n) m/s, at (i+1, n) m/s]
Numerical diffusion
The leading truncation error of an odd-order scheme (e.g. first-order upwind) behaves like a physical diffusion term. For with backward-space, forward-time:
The solution is smeared: peaks are lowered and sharp fronts spread out, although the true equation has no diffusion.
Numerical dispersion
For second-order (central) schemes the leading error term has an odd derivative, . Different wavelengths then travel at different speeds, so a sharp front produces spurious oscillations (ripples ahead of or behind the front). It is a phase error, with little change in amplitude.
Stability
A scheme is stable if errors (round-off or truncation) do not grow from step to step. For explicit schemes, the von Neumann or Courant-Friedrichs-Lewy condition requires
Implicit schemes (and the four-point scheme with ) are unconditionally stable, but a large still reduces accuracy.
Four-point implicit method
Data: , , , ; s, m, .
Time derivative
Space derivative
Answer: m/s and m/s.
✓ Answer checked by Claude Opus 5.5 (high effort)
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