- Practice · 8 marks
Derive shape functions of CST element
Short answer
For a linear triangle, shape functions are N_i=(a_i+b_i x+c_i y)/(2A), derived by solving nodal conditions. They satisfy Kronecker delta, sum to unity, and equal area coordinates. Strains are constant because b_i and c_i do not depend on x or y.
Derive the shape functions of a three-node linear triangular (constant strain triangle) element in terms of nodal coordinates. State their properties and explain why the element is called a constant strain triangle.
Consider a triangle with nodes 1, 2, 3 at , , numbered anticlockwise. Each node has two displacements , so the element has 6 degrees of freedom.
3 (x3,y3)
/ \
/ \
/ \
1-------2
Displacement field
Choose a complete linear polynomial (from Pascal's triangle):
Apply the nodal conditions for :
Solving by Cramer's rule, where the determinant of the matrix equals ( = area of triangle):
with
The same apply to , so
Properties
- at node and at the other two nodes.
- at every point (and , ).
- varies linearly along each edge and depends only on the two nodes of that edge, so displacements are continuous between adjacent elements.
- equal the area coordinates .
Why constant strain
The strains are
and depend only on the nodal coordinates, not on or . So the strains (and stresses) are the same everywhere inside the element.
✓ Answer checked by Claude Opus 5.5 (high effort)
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