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T1 and E1 frame structures and bit rates

Short answer

T1 frame: 24x8+1=193 bits per 125 us, rate 1.544 Mbps; E1 frame: 32x8=256 bits, rate 2.048 Mbps. NA hierarchy: T1 1.544, T2 6.312, T3 44.736, T4 274.176 Mbps. European: E1 2.048, E2 8.448, E3 34.368, E4 139.264, E5 564.992 Mbps.

Clarify the North American (T1) and European (E1) frame structures along with their multiplexing hierarchy, and for each hierarchical level provide the bit rate calculation.

Both systems use 8-bit PCM samples taken 8000 times per second, so each frame is 125 µs long and each voice channel is 64 kbps.

North American T1 frame

24 channels × 8 bits + 1 framing (F) bit. Signalling is robbed from the LSB of each channel in frames 6 and 12 of a 12-frame superframe.

 1 bit  8 bits  8 bits        8 bits
+-----+-------+-------+-----+--------+
|  F  |  Ch1  |  Ch2  | ... |  Ch24  |
+-----+-------+-------+-----+--------+
<--------- 193 bits in 125 us -------->
F = framing bit
Bits per frame=24×8+1=193 bitsFrame rate=8000 frames/s (T=125 μs)RT1=193×8000=1.544 Mbps\begin{aligned} \text{Bits per frame} &= 24 \times 8 + 1 = 193\ \text{bits} \\ \text{Frame rate} &= 8000\ \text{frames/s}\ (T = 125\ \mu\text{s}) \\ R_{T1} &= 193 \times 8000 = 1.544\ \text{Mbps} \end{aligned}

European E1 frame

32 time slots × 8 bits; TS0 = frame alignment, TS16 = signalling, 30 voice slots.

+-----+-----+-----+------+------+-----+------+
| TS0 | TS1 | ... | TS15 | TS16 | ... | TS31 |
+-----+-----+-----+------+------+-----+------+
 sync  <-voice 1-15->  sig   <-voice 16-30->
<------ 32 x 8 = 256 bits in 125 us ------->
Bits per frame=32×8=256 bitsRE1=256×8000=2.048 Mbps\begin{aligned} \text{Bits per frame} &= 32 \times 8 = 256\ \text{bits} \\ R_{E1} &= 256 \times 8000 = 2.048\ \text{Mbps} \end{aligned}

Multiplexing hierarchy and bit rates

North American:

LevelMade fromVoice channelsBit rateOverhead
DS01 voice channel164 kbps–
DS1 (T1)24 DS0241.544 Mbps8 kbps (framing)
DS2 (T2)4 DS1966.312 Mbps136 kbps
DS3 (T3)7 DS267244.736 Mbps552 kbps
DS4 (T4)6 DS34032274.176 Mbps5.76 Mbps
T2:4×1.544=6.176;  6.312−6.176=0.136 Mbps overheadT3:7×6.312=44.184;  44.736−44.184=0.552 Mbps overheadT4:6×44.736=268.416;  274.176−268.416=5.76 Mbps overhead\begin{aligned} T2 &: 4 \times 1.544 = 6.176;\ \ 6.312 - 6.176 = 0.136\ \text{Mbps overhead} \\ T3 &: 7 \times 6.312 = 44.184;\ \ 44.736 - 44.184 = 0.552\ \text{Mbps overhead} \\ T4 &: 6 \times 44.736 = 268.416;\ \ 274.176 - 268.416 = 5.76\ \text{Mbps overhead} \end{aligned}

European:

LevelMade fromVoice channelsBit rateOverhead
E01 voice channel164 kbps–
E130 voice + 2 TS302.048 Mbps128 kbps (TS0, TS16)
E24 E11208.448 Mbps256 kbps
E34 E248034.368 Mbps576 kbps
E44 E31920139.264 Mbps1.792 Mbps
E54 E47680564.992 Mbps7.936 Mbps
E2:4×2.048=8.192;  8.448−8.192=0.256 Mbps overheadE3:4×8.448=33.792;  34.368−33.792=0.576 Mbps overheadE4:4×34.368=137.472;  139.264−137.472=1.792 Mbps overheadE5:4×139.264=557.056;  564.992−557.056=7.936 Mbps overhead\begin{aligned} E2 &: 4 \times 2.048 = 8.192;\ \ 8.448 - 8.192 = 0.256\ \text{Mbps overhead} \\ E3 &: 4 \times 8.448 = 33.792;\ \ 34.368 - 33.792 = 0.576\ \text{Mbps overhead} \\ E4 &: 4 \times 34.368 = 137.472;\ \ 139.264 - 137.472 = 1.792\ \text{Mbps overhead} \\ E5 &: 4 \times 139.264 = 557.056;\ \ 564.992 - 557.056 = 7.936\ \text{Mbps overhead} \end{aligned}

The extra bits at each higher level are used for frame alignment, pulse stuffing (justification) control and alarms, because the tributaries are plesiochronous.

✓ Answer checked by Claude Opus 5.5 (high effort)

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