- 2073 Shrawan · 4 marks
Inductance from flux linkages
Short answer
Inductance L equals flux linkage NΦ divided by current i. From Faraday’s law, induced emf e = -L di/dt; thus L = N dΦ/di = e/(di/dt). 1 H corresponds to 1 Wb-turn/A or 1 V per A/s.
Derive an equation for inductance L in terms of flux linkages and current change.
Inductance L of a coil is the flux linkage produced per unit current. Consider a coil of N turns carrying current i. Let φ be the flux linking each turn.
Derivation
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The flux produced is proportional to the current (for a linear magnetic path), so the flux linkage is proportional to i:
Nφ = L i ⟹ L = Nφ / i
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When the current changes, the flux linkage changes. By Faraday's law the induced emf is
e = −d(Nφ)/dt = −N dφ/dt
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Since Nφ = L i and L is constant,
e = −L di/dt
The negative sign shows (Lenz's law) that the induced emf opposes the change of current.
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Taking magnitudes, the inductance in terms of flux linkage and current change is
L = N dφ / di = e / (di/dt)
For a finite change: L = N Δφ / Δi = Δ(flux linkage) / Δi.
So 1 henry means 1 weber-turn of flux linkage per ampere, or 1 V induced when current changes at 1 A/s.
✓ Answer checked by Claude Opus 5.5 (high effort)
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