- Asked 2/15
- 2069 Chaitra · 4 marks
- 2067 Asoj · 8 marks
Inductance and inductors in parallel
Short answer
Inductance is the property of a coil opposing current change, defined as flux linkage per ampere (L = NΦ/I). In parallel without mutual coupling, voltage is same across all, so current change rates sum; therefore 1/L_eq = 1/L1 + 1/L2 + 1/L3.
Define inductance and derive relation for connection of inductors connected in parallel connection.
Inductance
Inductance (L) is the property of a coil by which it opposes any change of current through it. It is the flux linkage per ampere:
L = NΦ/I (henry)
From Faraday's law, the induced EMF is e = −L di/dt, so L is the EMF induced per unit rate of change of current. 1 henry produces 1 volt when the current changes at 1 A/s.
Inductors in parallel (no mutual coupling)
i1 →
+---(L1)---+
i → | i2 → |
o---------+---(L2)---+---------o
| i3 → |
+---(L3)---+
All inductors have the same voltage v across them, and the supply current divides: i = i₁ + i₂ + i₃.
For each inductor, v = L di/dt, so
di₁/dt = v/L₁, di₂/dt = v/L₂, di₃/dt = v/L₃
Differentiate the current equation:
di/dt = di₁/dt + di₂/dt + di₃/dt = v (1/L₁ + 1/L₂ + 1/L₃)
For the equivalent inductor, di/dt = v/L_eq, so
1/L_eq = 1/L₁ + 1/L₂ + 1/L₃
For two inductors: L_eq = L₁L₂/(L₁ + L₂).
Notes
- L_eq is smaller than the smallest inductance.
- The current divides inversely to the inductances: i₁ = i × L₂/(L₁ + L₂).
- Example: 6 H and 3 H in parallel give 2 H.
- If the coils are magnetically coupled with mutual inductance M, L_eq = (L₁L₂ − M²)/(L₁ + L₂ ∓ 2M) (minus for aiding flux, plus for opposing).
✓ Answer checked by Claude Opus 5.5 (high effort)
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